Calculus help please
Solve the problem: The sales in thousands of a new type of product are given by s(t)=100-60e^-0.8t when t=3

I would think the s'(3)=144 thousand, but the answer is 4.4 thousand

Question

Calculus help please
Solve the problem: The sales in thousands of a new type of product are given by s(t)=100-60e^-0.8t when t=3

I would think the s'(3)=144 thousand, but the answer is 4.4 thousand

zepdrix · Answer

$$\large\rm s(t)=100-60e^{-0.8t}$$$$\large\rm s'(t)=0-60e^{-0.8t}\cdot(-0.8)$$

zepdrix · Answer

Derivative of 100 is simply 0.
Maybe that's what was making your answer so large.
Hmm, forget chain rule also maybe?

anonymous · Answer

I forget chain rule. Thank you