Margie calculated that she would spend $175 on school supplies this year. She actually spent $97.50 on school supplies. What is Margie’s percent of error?
77.3%
79.5%
44.2%
4.4%
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OpenStudy (anonymous):
@johnweldon1993 !!!!!!
OpenStudy (anonymous):
I want to make sure im right!
OpenStudy (johnweldon1993):
What'd you get? :)
OpenStudy (anonymous):
B??
OpenStudy (anonymous):
79.5?
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OpenStudy (johnweldon1993):
How did you get that?
OpenStudy (johnweldon1993):
Ehh nvm, I just like showing the process haha you're correct :P
OpenStudy (anonymous):
\[\frac{ 77.5 }{ 97.5 }\times100 =79.48717949 \]
OpenStudy (johnweldon1993):
\[\large \color \red \checkmark\] BAM!
OpenStudy (richgall____):
its actually C
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OpenStudy (richgall____):
i was looking at similar problems like yours and most ppl cam up with 44.2
OpenStudy (anonymous):
but also \[175-97.50=77.5\]
OpenStudy (johnweldon1993):
\[\large \text{% Error} = \frac{\text{Theoretical Value - Experimental Value}}{\text{Theoretical Value}}\]
OpenStudy (richgall____):
yea ik but u have to find the percent of what 77.5 was of that
OpenStudy (richgall____):
why would they make the problem that simple i mean come on
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OpenStudy (anonymous):
\[\frac{ 77.5 }{ 97.5 }=79.48717949\] there you go :P :)
OpenStudy (richgall____):
now i understand it better lol okay ;)
OpenStudy (johnweldon1993):
I believe what other people are thinking...is
\[\large \frac{97.5}{175} = 55.7 \text{ Percent}\]
That is the amount she was correct...so they think 1 - that = 44.3 would be the percent she is wrong...but that is an incorrect observation