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Mathematics 35 Online
OpenStudy (anonymous):

this is my last question. someone help.

OpenStudy (anonymous):

OpenStudy (anonymous):

Calculate the area of both shapes

OpenStudy (anonymous):

Yes, I got that. But I need help on getting there.

OpenStudy (anonymous):

Cool. So, do you know how to calculate the area of a rectangle?

OpenStudy (anonymous):

P= area of circle/area of rect.?

OpenStudy (anonymous):

I think so.

OpenStudy (anonymous):

in this problem, would the rectangle be 1.92?

OpenStudy (anonymous):

Yep. So A(rectangle) = base x height \[and A(circle) = \pi r ^{2}\]

OpenStudy (anonymous):

What do I do next?

OpenStudy (anonymous):

Yep. A(rectangle) = (1+1.4) x (0.8) = 1.92

OpenStudy (anonymous):

So once you've got the area of the rectangle you need the area of the circle

OpenStudy (anonymous):

It would be 0.5 because the radius is 0.4

OpenStudy (anonymous):

Yeah A(circle) = 0.4^2 x 3.1415...

OpenStudy (anonymous):

So then, as you said, P= area of circle/area of rect Simply calculate, using the values that we worked out

OpenStudy (anonymous):

How do put that in equation?

OpenStudy (anonymous):

P = (0.5) / (1.92)

OpenStudy (anonymous):

0.26

OpenStudy (anonymous):

.

OpenStudy (anonymous):

Exactly

OpenStudy (anonymous):

I have these other ones, all I need is someone to check if its right.

OpenStudy (anonymous):

answer b

OpenStudy (anonymous):

I agree

OpenStudy (anonymous):

answer b.

OpenStudy (anonymous):

@jayzdd is the last question correct?

OpenStudy (anonymous):

you got b?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

I'm guessing its wrong?

OpenStudy (anonymous):

the circle has area pi * (.8/2)^2

OpenStudy (anonymous):

the rectangle has three regions, the left of the circle region of the circle, the circle itself, and the right of the circle region

OpenStudy (anonymous):

So what's the equation for it?

OpenStudy (anonymous):

lets look at this square here http://prntscr.com/91dlno

OpenStudy (anonymous):

it has total area 1.0 * 0.8 = .8 we want to find the probability of falling into the area outside the semicircle

OpenStudy (anonymous):

the semicircle area is 1/2 * pi * (.4)^2 the area to the left of the semicircle is (1.0)*(.8) - 1/2 * pi * (.4^2) divide this by total area (1.0)*(0.8)

OpenStudy (anonymous):

So calculate (1.0)*(0.8) - 1/2 * pi * (0.4^2) first

OpenStudy (anonymous):

we are trying to find the probability of falling into the green area http://prntscr.com/91do6n

OpenStudy (anonymous):

is the square of (0.4^2) meant to be inside or outside?

OpenStudy (anonymous):

Do you agree that green area + blue area = total area

OpenStudy (anonymous):

Yes I got that

OpenStudy (anonymous):

green area + blue area = total area plugging in: green area + 1/2* pi * (.4)^2 = 1.0 * (0.8) solve for green area green area = 1.0 * (0.8) - 1/2* pi * (.4)^2

OpenStudy (anonymous):

Yes I got 0.54

OpenStudy (anonymous):

probability of falling into green = green area / total area = .54 / ( 1.0 * 0.8)

OpenStudy (anonymous):

actually its better if you keep more decimals = .54867 / ( 0.8 ) = .6858 this rounds to .69

OpenStudy (anonymous):

are we good?

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