it has total area 1.0 * 0.8 = .8
we want to find the probability of falling into
the area outside the semicircle
OpenStudy (anonymous):
the semicircle area is 1/2 * pi * (.4)^2
the area to the left of the semicircle is
(1.0)*(.8) - 1/2 * pi * (.4^2)
divide this by total area (1.0)*(0.8)
OpenStudy (anonymous):
So calculate (1.0)*(0.8) - 1/2 * pi * (0.4^2) first
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OpenStudy (anonymous):
is the square of (0.4^2) meant to be inside or outside?
OpenStudy (anonymous):
Do you agree that
green area + blue area = total area
OpenStudy (anonymous):
Yes I got that
OpenStudy (anonymous):
green area + blue area = total area
plugging in:
green area + 1/2* pi * (.4)^2 = 1.0 * (0.8)
solve for green area
green area = 1.0 * (0.8) - 1/2* pi * (.4)^2
OpenStudy (anonymous):
Yes I got 0.54
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OpenStudy (anonymous):
probability of falling into green
= green area / total area
= .54 / ( 1.0 * 0.8)
OpenStudy (anonymous):
actually its better if you keep more decimals
= .54867 / ( 0.8 ) = .6858
this rounds to .69