Question

How go from a contract logarithm form to expanded logarithm form?

log(3x-3y)

Answer 1

Hey there :)
\[\rm \log[3x-3y]\]

Answer 2

Let's start by factoring a 3 out of each the x and the y,\[\rm \log[3(x-y)]\]

Answer 3

yes

Answer 4

Thank you for helping me btw!

Answer 5

very much appreciated

Answer 6

Recall your Log Product Rule:\[\rm \log(a\cdot b)=\log(a)+\log(b)\]

Answer 7

Do you see how we can apply that to our problem maybe?\[\rm \log[3\cdot(x-y)]\]Do you see which two things are being multiplied together?

Answer 8

yes the 3 and (x-y)

Answer 9

Good :)
So how is that going to break down using the rule?
Can you figure it out?

Answer 10

log(3)+log(x-y)

Answer 11

Ah yes! Good job!
That's pretty much all we can do with this one.

Answer 12

oh!!! really!!!

Answer 13

thats it?

Answer 14

The x and the y are being subtracted,
we don't have a special rule for that unfortunately.

Answer 15

there were a couple different ones i was stuck on as well

Answer 16

k let's check em out :)