Find the value of A1 for an infinite geometric series with S = -45 and R=-1/9

Question

tkhunny · Answer

Please show YOUR work.

Do you have a formula for such a sum?  Maybe: $S = \dfrac{A_{1}}{1-r}$?

Please substitute known values and solve for the remaining value.

anonymous · Answer

-45=A1/1+.111111 
A1=-45*1+.11111
A1=-44????

anonymous · Answer

tkhunny

anonymous · Answer

-50

tkhunny · Answer

Try again.
Please be more careful with your notation

A1/1 - b = (a1/1) - b

You mean A1/(1 - b)

 and don't use a calculator.  Keep the fractions.

anonymous · Answer

the computer doesnt accept the fractions it tells me to change to decimal

tkhunny · Answer

Use a piece of paper.  Format the answer as required.

tkhunny · Answer

1 + 1/9  = 9/9 + 1/9 = 10/9

You don't need a calculator for that.