Question

Having trouble figuring out how to remove duplicate counts in probability.

Answer 1

2. There are 3 possible configurations to have 6 consecutive ones in a binary string of length 8.
1st Option – 6 ones from position 1 to 6.
2nd Option – 6 ones from position 2 to 7.
3rd Option – 6 ones from position 3 to 8.

However, need to exclude duplicate cases.

Answer 2

@dan815

Answer 3

okay

Answer 4

when its all 1s it exists in all 3
when its 1s from 1 to 7 it exists in first 2
when its 1s fro 2 to 8 it exists in last 2

Answer 5

2^8 - 6

Answer 6

Is there a methodical way to think about this? or do i need to always jsut consider different cases?

Answer 7

umm i dunno i just thouht about it like this

Answer 8

so
u can have all 1s there is 1 for this
7 of 1s-- there are 2 for this
6 of 1s -- there are 3 arrangements for htis

1+2+3=6

Answer 9

oh wait there are more umm

Answer 10

kk, that makes sense. Thank you!

Answer 11

no theres more to it than just that let me think

Answer 12

the
8 of 1s
7 of 1s case is fine

Answer 13

now for the 6 of 1s

Answer 14

there are actually 5 cases