OpenStudy (anonymous):

The initial point for a vector is the origin, and θ denotes the angle (measured counterclockwise) from the x-axis to the vector. Compute the horizontal component Vx and vertical component Vy of the given vector. (Round your answers to two decimal places.) The magnitude of V is 44 cm/sec, and θ = 50° Vx = cm/sec Vy = cm/sec

2 years ago
OpenStudy (anonymous):

anyonneeee?

2 years ago
OpenStudy (johnweldon1993):

|dw:1447737139537:dw|

2 years ago
OpenStudy (johnweldon1993):

Now, as we know, we can break a vector into its vertical and horizontal components |dw:1447737216270:dw|

2 years ago
OpenStudy (johnweldon1993):

Now, if I were to relabel that and exploit the components...wouldnt we just have a right triangle? |dw:1447737301444:dw|

2 years ago
OpenStudy (johnweldon1993):

Now we can just use basic trig to solve for the components of the vector Knowing \(\large cos(x) = \frac{adjacent}{hypotenuse}\) and \(\large sin(x) = \frac{opposite}{hypotenuse}\) We can apply this here \(\large cos(50) = \frac{V_x}{44}\) and \(\large sin(50) = \frac{V_y}{44}\) and solve for \(\large V_x\) and \(\large V_y\) respectively

2 years ago
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