Question

The initial point for a vector is the origin, and θ denotes the angle (measured counterclockwise) from the x-axis to the vector. Compute the horizontal component
Vx
and vertical component
Vy
of the given vector. (Round your answers to two decimal places.)
The magnitude of V is 44 cm/sec, and θ = 50°
Vx = cm/sec
Vy = cm/sec

Answer 1

anyonneeee?

Answer 2

Now, as we know, we can break a vector into its vertical and horizontal components

Answer 3

Now, if I were to relabel that and exploit the components...wouldnt we just have a right triangle?

Answer 4

Now we can just use basic trig to solve for the components of the vector

Knowing \(\large cos(x) = \frac{adjacent}{hypotenuse}\) and \(\large sin(x) = \frac{opposite}{hypotenuse}\)

We can apply this here

\(\large cos(50) = \frac{V_x}{44}\) and \(\large sin(50) = \frac{V_y}{44}\) and solve for \(\large V_x\) and \(\large V_y\) respectively