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Mathematics 17 Online
OpenStudy (anonymous):

help? http://prntscr.com/97ujxx http://prntscr.com/97ukj1

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

substitute A=36pi cm^2 into this equation

OpenStudy (anonymous):

\[c=2\sqrt{A~\pi}\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[C=2\sqrt{36\pi(\pi)}\]

OpenStudy (anonymous):

i got A

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

ok cx

OpenStudy (anonymous):

for #2 is x = 2 the extraneous root?

Directrix (directrix):

Let's see.

OpenStudy (anonymous):

For the second question... you could check by replacing x with the given options and verifying it works by seeing if both sides are the same thing

Directrix (directrix):

I agree with B)2 as the exraneous root. How about you, @MARC_ |dw:1448699140539:dw|

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