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Since the first equation is already solved for x, use substitution. Where you see x in the second equation, replace it with 4y + 6. Now you have an equation in just y, so solve it for y. Once you have y, substitute into the first equation and solve for x.
Or in other words... x=4y+6 <---equation 1 x-3y=4 <---equation 2 They tell you the value of x so just take equation 1 and plug it into equation 2 \[\huge~\rm~\bf4y+6-3y=4\] From here solve for y
5y?
Let's do that part together perhaps it'll enhance your understanding :) \[ \huge~\rm~ 4y+6−3y=4 \] Ok the first step is to combine like terms \[\huge~\rm\bf ~4y-3y=? \]
y
1y
Good :) \[\huge~\rm~1y+6=4\] Next step is to subtract 6 from both sides \[\huge~\rm~1y+6-6=4-6\] \[\huge~\rm~1y=4-6\] \[\huge~\rm~4-6=?\]
-2
Good! :) 1y=-2 divide both sides by 1 1/1=y y=-2/1 -2 divided by 1 =?
-2
Good so we get y=-2 :)
Now to solve for x Plug in the y value into equation 1 \[\huge~\rm~\bf~x=4(-2)+6 \]
4 x -2=?
1y is the same as y. There is no need to divide both sides by 1. Once you have 1y = -2, it's the same as having y = -2. In fact, you can simply write that 4y - 3y = y, and leave out the 1.
-8
Good -8+6=?
-2
(-2,-2)
Agreed well done :)
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