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OpenStudy (mathstudent55):
Since the first equation is already solved for x, use substitution.
Where you see x in the second equation, replace it with 4y + 6.
Now you have an equation in just y, so solve it for y.
Once you have y, substitute into the first equation and solve for x.
pooja195 (pooja195):
Or in other words...
x=4y+6 <---equation 1
x-3y=4 <---equation 2
They tell you the value of x so just take equation 1 and plug it into equation 2
\[\huge~\rm~\bf4y+6-3y=4\]
From here solve for y
OpenStudy (gokuporter):
5y?
pooja195 (pooja195):
Let's do that part together perhaps it'll enhance your understanding :)
\[ \huge~\rm~ 4y+6−3y=4 \]
Ok the first step is to combine like terms
\[\huge~\rm\bf ~4y-3y=? \]
OpenStudy (gokuporter):
y
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OpenStudy (gokuporter):
1y
pooja195 (pooja195):
Good :)
\[\huge~\rm~1y+6=4\]
Next step is to subtract 6 from both sides
\[\huge~\rm~1y+6-6=4-6\]
\[\huge~\rm~1y=4-6\]
\[\huge~\rm~4-6=?\]
OpenStudy (gokuporter):
-2
pooja195 (pooja195):
Good! :)
1y=-2
divide both sides by 1
1/1=y
y=-2/1
-2 divided by 1 =?
OpenStudy (gokuporter):
-2
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pooja195 (pooja195):
Good so we get y=-2 :)
pooja195 (pooja195):
Now to solve for x
Plug in the y value into equation 1
\[\huge~\rm~\bf~x=4(-2)+6 \]
pooja195 (pooja195):
4 x -2=?
OpenStudy (mathstudent55):
1y is the same as y.
There is no need to divide both sides by 1.
Once you have 1y = -2, it's the same as having y = -2.
In fact, you can simply write that 4y - 3y = y, and leave out the 1.
OpenStudy (gokuporter):
-8
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