Question

The area of a rectangle is
63 yd2
, and the length of the rectangle is
11 yd
more than twice the width. Find the dimensions of the rectangle.

Answer 1

hello :)

Answer 2

hey

Answer 3

welcome to openstudy, anywho lets jump straight into the problem :D

Answer 4

do you know what the formula for the area of a rectangle is?

Answer 5

what ive gotten is 63=(2w+11)(w)

Answer 6

why do you have a w outside of the first parenthesis

Answer 7

the first part is correwct

Answer 8

63 (Area) = 11 x w

Answer 9

not 2 w

Answer 10

oh wait

Answer 11

lol

Answer 12

u know what, let me solve it on my end real quick :D

Answer 13

ok

Answer 14

so we have 63 = 11 * x

Answer 15

this word problem gives u uneeded information in a hopes to confuse u

Answer 16

for example when it says "more than twice the width"

Answer 17

this doesnt really matter

Answer 18

what matters is that we know the length is 11 and the area is 63

Answer 19

so to solve this we use alebra :D

Answer 20

in other words we isolate the variable

Answer 21

to do this we divide both sides by 11

Answer 22

so we get 63/11 = x

Answer 23

which would give u the answer of...?

Answer 24

5.7

Answer 25

yup :D

Answer 26

which follows what your word problem says, the length is more than twice the width :)

Answer 27

well have a good night ^.^

Answer 28

thank you

Answer 29

oh dont forget to hit the "Best Response" button :D

Answer 30

it helps me out :3

Answer 31

anyways have a good day :d