Calculating solubility!

The molar solubility of Ag2CO3 is 1.2 x 10^-4 M at 25 degrees Celsius (room temperature).

Express this value in grams per 100.0 ml.

Question

Calculating solubility!

The molar solubility of Ag2CO3 is 1.2 x 10^-4 M at 25 degrees Celsius (room temperature).

Express this value in grams per 100.0 ml.

jfraser · Answer

the solubility is given in $M$, or $\frac{mol}{L}$, you need to convert that into a $different$ unit, $\frac{g}{100.mL}$

korosh23 · Answer

At the end when I get grams, can I just divide it by 100 mL, would that work?

jfraser · Answer

you actually divide it by 10, because in 1000mL, there are 10 100mL increments