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HI!!
\[2\sin^2(x)=\cos(x)\]?
start by writing all in terms of cosine i.e use \[\sin^2(x)=1-\cos^2(x)\] then you will have a quadratic equation to solve in terms of cosine only
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start with \[2(1-\cos^2(x))=\cos(x)\]
Is this: 2sin^2x=2 c+osx 2sin^2x=2 cosx or something else
or, 2sin^2x=2 + cosx
the second one @dir
2 sin² (x) = 2 + cos (x) This is not the same one that Misty used. Maybe you could check your text one more time to see if this is it. Also, I don't see any instructions. @cutegirl
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