Question

Trigonometric Functions @ganeshie8

Answer 1

\[Solve~the~following~equation~for~0\le~x~\le360\]

Answer 2

\[\sin2x=1\]

Answer 3

The first value is 45 but i'm not sure how to find the second value

Answer 4

let u=2x
then x=u/2
so you have 0<=u/2<=360
solving for u we get 0<=u<=720

so first step
solve sin(u)=1 on the interval [0,720]

Answer 5

then once you find u
then you can replace u with 2x
and solve for x

Answer 6

\[u=90\]\[x=\frac{ 90 }{ 2 }\]\[x=45\]is it correct? @freckles

Answer 7

ok but there are other u in the interval such that sin(u)=1

Answer 8

you have
sin(u)=1
when u=90,90+360
and so 2x=90,90+360
so x=90/2 or x=(90+360)/2

Answer 9

@MARC_

Answer 10

\[x=45,225\]

Answer 11

Thank you @freckles :)

Answer 12

np