Can someone explain this to me, Medal and Fan!!! Using the completing-the-square method, find the vertex of the function f(x) = 2x2 − 8x + 6 and indicate whether it is a minimum or a maximum and at what point. Maximum at (2, –2) Minimum at (2, –2) Maximum at (2, 6) Minimum at (2, 6)
To write in completed square form, the equation has to be in form \[x^2+ax+b\], meaning, it has to be divided by to to have the x^2 with coefficient 1., giving:\[x^2-4x+3\] Writing in completed square form, consists in putting in brackets squared the x, the sign of a and half its coefficient. At the end, you put the b value with its sign as well, giving\[(x-2)^2-4+3=(x-2)^2-1\]
The equation written is in the form\[(x-p)^2+q\], where x vertex is p and y vertex is q. The coordinates will then be (2,-1). Look at the sign behind (x-p)^2: It is positive, meaning, the graph is u-shaped. Hence the vertices are at a minimum.
Thank you so much, you made this soo much easier.
No problem.
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