Find all solutions to the equation. 7 sin^2x - 14 sin x + 2 = -5
I have a basic understanding for these types of problems, I am just having some difficulty with this one.
\[7 u^2 - 14 u + 2 = -5\]
Yes just like that
For other problems I have factored, Im just not sure what to do with this one. Should I subtract -2 from both sides? Should I factor out the 7 from both sin terms?
\[7 u^2 - 14 u + 7=0\]
Okay thats what I did the first time. I then factored out 7 to be left with \[7(\sin^2x-2sinx+1)=0\]
\[7(\sin(x)-1)^2=0\]
That was the point where I ended. I didnt know where to take it from there.
\[\Large\Rightarrow \sin(x)-1=0\]
Which we would need to isolate the sin to get \[sinx=1\]
What happens to the 7 though?
divide both sides by 7
so sinx=1/7? The only thing that confuses me about that, is that there is no sine or y value on the unit circle that is 1/7
no
\[7(\sin(x)-1)^2=0\] \[\Rightarrow (\sin(x)-1)^2=0/7=0\]
so you need just to find \[\sin(x)=1\]
how does 0/7=0?
ohhhhh
Nevermind I get it now
zero divided by any nonzero number is zero
Thank you so much!
That would be like multiplication. 0 times any number is zero.
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