Determine the most efficient way to use the Binomial Theorem to show the following. (11)^4=14641 a.write 11-5+6 and expand. b.write 11=10+1 and expand. c.write 11=3+3+2 and expand. d.write 11=4+4+3 and expand.
@JoeDeWise
here
Okay! I posted my question
114 =11*11*11*11 =114 =14641
So?
I would prefer myself to evaluate powers of 10 or powers of 1 because they are extremely easy.
What do you mean?
for example which one seems easier? 5^4? 10^4? also c doesn't make sense because 3+3+2 is totally not 11 also 11=4+4+3 seems like it might be harder to use binomial theorem since 4+4+3 consist of 3 terms. But I guess you do binomial again and again to expand (4+4+3)^4.
what do I mean about what?
10^4 seems easier
right
10^4=10000 but 5^4 I would have to go back to multiplying 5*5*5*5 to figure out
Would it be B?
yes in my opinion expanding (10+1)^4 using binomial theorem is tons easier because like I said before evaluating powers of 10 and evaluating powers of 1 are way easy
\[(a+b)^4=a^4+4 \cdot a^3 b+6 \cdot a^2b^2 + 4 \cdot ab^3+b^4 \\ \text{ so } (10+1)^4=10^4+4 \cdot 10^3(1)+6 \cdot 10^2(1)^2+4 \cdot 10(1)^3+1^4\] try evaluating to see how easy that is
It was B.! Thank you! Could you help me with three more?
I can try
Use Pascal's Triangle to expand the binomial (d-3)^6
well using pascal's triangle what are the coefficients in the (6+1)th row?
I am unsure
so you don't know where the 7th row is?
I don't understand Pascal's Triangle..
|dw:1449683889849:dw| here I wrote 6 rows
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