Question

Two planets - planet A and planet B - are orbiting a star.If planet A has an orbital radius which is four times as large as planet B then the period of planet A orbit is _ times larger than the period of Planet B orbit

Answer 1

Applying Kepler's law of harmonies to this situation would result in:

TA2 / RA3 = TB2 / RB3
This equation can be algebraically rearranged to

TA2 / TB2 = RA3 / RB3
The ratio of the period squared of planet A to planet B will be equal to the ratio of the radius cubed of planet A to planet B. The ratio of the radii of the two planets is given - planet A's radius is two (or three) times larger than planet B's radius. The cube of this ratio is equal to the square of the ratio of the period. Taking the square root of the period squared ratio will yield the ratio of the periods of the planets. Mathematically, this could be written as

TA / TB = SQRT(TA2 / TB2) = SQRT(RA3 / RB3)

Answer 2

answer 8

Answer 3

can u plug in the number

Answer 4

can u help me plug in the numbers

Answer 5

@pooja195 I am blanking out on this can you help?

Answer 6

@Loser66 can you help I am blanking out.

Answer 7

@zepdrix

Answer 8

Ta2 / Tb2 = Ra3 / Rb3

Answer 9

Sorry I am trying to remember.

Answer 10

i know the answer is 8 but i cant put it in the formula

Answer 11

Wait how do you know the answer is 8 if you don't know how to input it?

Answer 12

i didnt use the formula thats why i tried doing 4^3=sqrt64 which equals 8

Answer 13

I can't remember sorry I wouldn't want to give you the wrong information.

Answer 14

can u help me understand the formula

Answer 15

T2 = kr3 . In every day terms, T is the time of the orbital period of the planet, K is a constant, and r is the ratio of the Sun to the planet. If more than on planet is involved, the ratio becomes (Ta2 / Tb2 ) = (Ra3 / Rb3 ). This is still used today to find distances of objects found inside the Milky Way.

Answer 16

can u plug it in

Answer 17

Can you tell me what eight is?

Answer 18

eight is the answer

Answer 19

Ok answer to what. The whole problem? Because I cannot give you straight answers I want you to help come to the answer so that you understand it.

Answer 20

Where did you get the answer?

Answer 21

i did this √4³ = 8

Answer 22

this is the answer to the whole problem but i dont know how to put it into your formula

Answer 23

Are you working with Kepler?

Answer 24

yes

Answer 25

TA / TB = SQRT(TA2 / TB2) = SQRT(RA3 / RB3) is this the formula

Answer 26

Yes now do you know what the satellite mean orbital radius is?

Answer 27

planet a orbital radius is 4 times as larger as planet B

Answer 28

Ok so what is planet B

Answer 29

What is the planetary mass?

Answer 30

2 pie idk

Answer 31

Here is a file that will help

Answer 32

By performing simple mathematics for planet A and B

T(A)^2 / T(B)^2 = R(A)^3 / R(B)^3

Given R(A) = 4X R(B)

T(A)^2 / T(B)^2 = 64 (As 4X4X4=64)

T(A) / T(B) = 8

Thus Planet A takes 64 takes 8 times of Time Period over Planet B

so answer is 8 times

Answer 33

Correct how did you find it?

Answer 34

looked at the previous formula and assume the radius

Answer 35

Nice!

Answer 36

Did you see my file though?

Answer 37

yes thanks for the help

Answer 38

No problem sorry I couldn't help more.