Question

Find the absolute value of the complex number.

1. |-4+3i|

Answer 1

absolute value is =sqrt{(-4)^2+(3)^2}=sqrt(16+9)=sqrt(25)=ans

Answer 2

alright thanks!

Answer 3

ans=sqrt(25)=5

Answer 4

Could you help me with one more?

Answer 5

How would you do |-10+8i|

Answer 6

I got sqaure root 164

Answer 7

what would the next step be

Answer 8

@Er.Mohd.AMIR

Answer 9

Try this website:
https://mathway.com/
It should help. : )

Answer 10

howd you get sqrt 2x9x9

Answer 11

sorry 164=2*82

Answer 12

@Er.Mohd.AMIR oneeee more questoin haha sorry for |-10+6i| = 2 sqrt 17 ?

Answer 13

sqrt 164 is ans or use calculator to find it.

Answer 14

next quickly please

Answer 15

oh thats all but my paper says the answers is 2 sqrt 34

Answer 16

for |-10+6i|

Answer 17

oh sqrt{(10)^2+(6)^2}=sqrt(100+36)=sqrt(136)=sqrt(2*2*34)=2 sqrt(34) is ans

Answer 18

couldn't you simplifity it more? to make it 2 sqrt 17 ?

Answer 19

fine

Answer 20

more

Answer 21

that was it, but couldn't you simplifity it evne more?

Answer 22

2 sqrt 34 to 2 sqrt 17

Answer 23

no sqrt(x*x)=x if two number are same in sqrt one come out only

Answer 24

hmmm, i still don't get it

Answer 25

if which two numbers are the same?

Answer 26

sqrt(136)=sqrt(2*2*34)=2 sqrt(34) s number two is same so out it 34=2*17 no number is same

Answer 27

off

Answer 28

OHHH okay i see now, thank you!!

Answer 29

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