Question

1.Solve
| x-1/5|=3

A.x=-14/5 or x=16/5
B.x=14/5 or x=-16/5
C.x=-14/5 or x=-16/5
D.x=14/5 or x=16/5 *****

2.The table shows the relationship between two variables. Which selection describes the relationship?
X=1, 2, 3, 4
Y=2, -3, -8, -13

A.increasing; linear
B.increasing; nonlinear
C.decreasing; linear *****
D.decreasing; nonlinear

please correct me if im wrong

Answer 1

Is that \[\frac{ x-1 }{ 5 }=3\] ?

Answer 2

no @PhantomCrow I corrected it. (I edited it) please look up at #1 for the correct problem I had to fix it since I done it wrong :)

Answer 3

So is it \[|x-\frac{ 1 }{ 5 }|=3\] ?

Answer 4

If so, you can begin by negating the absolute value and adding a positive/negative sign to three.

Answer 5

yes :)

Answer 6

We do this because the absolute value of anything has to be positive, regardless of the value within the bars. So we should account for both negative and positive values.

Answer 7

After this, we split the equation up into two separate solutions and solve for x in each one.

Answer 8

how do I do that @PhantomCrow

Answer 9

\[|x-\frac{ 1 }{ 5 }|=3\]
\[x-\frac{ 1 }{ 5 }=\pm3\]
\[x-\frac{ 1 }{ 5 }=3\] and \[x-\frac{ 1 }{ 5 }=-3\]

Answer 10

??? @PhantomCrow

Answer 11

What don't you understand?

Answer 12

Remember that the absolute value of anything must be positive. So no matter what we put into x with the absolute value bars around it, it ill output a positive number. There can only be two possible values for x-1/5 --3 and negative 3 because we are taking the absolute value of it and regardless of its sign, we will get a positive number so we should account for the negative values in the absolute value bars as well as the positive ones. So if the absolute value bars were not there, the answer could remain as 3 or potentially change to -3.

Answer 13

oh okay but for #1 I thought it was D and for #2 I thought it was C and im not sure if I was correct or not @PhantomCrow

Answer 14

Did you solve the two equations we derived for the first one?

Answer 15

Break down the problem into these 2 equations
\[x-1/5=3 -(x-1/5)=3\]

Answer 16

the first one is not D @CookieMonster18

Answer 17

\[x=3+\frac{ 1 }{ 5 }\]
\[x=-3+\frac{ 1 }{ 5 }\]

Answer 18

| x-1/5|=3 can be broken down into two separate equations:

\[x-\frac{ 1 }{ 5 }=3, and\]

Answer 19

\[-(x-\frac{ 1 }{ 5 })=3\]

Answer 20

A?? because is x=16/5 -1/5 it'll equal 3

Answer 21

We have two solutions for x.

Answer 22

Eliminating the fraction 1/5 will make the solution easier. Multiply both equations by 5 to do this (multiply every term).

Sove the resulting equations.

You'll get two separate solutions.

Answer 23

yes it would be A you just forgot the negative

Answer 24

Again, expect TWO solutions, and be sure to check both.

Answer 25

@Crystal_Bliss what do you mean I forgot the negative?? for #1 A?? you mean x=-14/5??

Answer 26

@pooja195 am I correct? #1 is A and #2 is C??