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Mathematics 21 Online
OpenStudy (anonymous):

FAN AND MEDAL please help!! i need just this and I am done https://i.gyazo.com/2047156677840b0159a41ab7db4214ce.png ???? How do I do this

OpenStudy (anonymous):

@jim_thompson5910 Hey if you aren't busy, do you know how to do this??

OpenStudy (anonymous):

you have to use pythagorean theorem twice AB^2 + BC^2 = AC^2 then AC^2 + CD^2 = AD^2

OpenStudy (anonymous):

How do I get the lengths of AC to do this?

OpenStudy (anonymous):

use the square root AC^2 = AB^2 + BC^2 AC = √ ( AB^2 + BC^2)

OpenStudy (anonymous):

Ok I did it and the square root of 24 would be 4.898 but without square rooting it its just 24

OpenStudy (anonymous):

so AC is 24??

OpenStudy (anonymous):

AC = √ 12^2 + 12^2 AC = √ 288

OpenStudy (anonymous):

16.970 is what I get when I Square root 288 so ac is 16.970/17 if we round it?

OpenStudy (anonymous):

its better if you dont approximate it AC = √288 now plug it into the second pythagorean equation AC^2 + CD^2 = AD^2

OpenStudy (anonymous):

24.97 So AD is 24.97?

OpenStudy (anonymous):

AC^2 + CD^2 = AD^2 √(288)^2 + 8^2 = AD^2 288 + 64 = AD^2 352 = AD^2 AD = √352

OpenStudy (anonymous):

18.761 then?

OpenStudy (anonymous):

which is 18.76 to the nearest hundredth

OpenStudy (anonymous):

Thank you !! That's all or?

OpenStudy (anonymous):

thats it. :)

OpenStudy (anonymous):

I appreciate your help !! You are very smart

OpenStudy (anonymous):

thanks. do you see how there are two right triangles http://prntscr.com/9eqr93

OpenStudy (anonymous):

Yes !! I see them now

OpenStudy (anonymous):

Yes !! I see them now

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