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OpenStudy (anonymous):
FAN AND MEDAL please help!! i need just this and I am done
https://i.gyazo.com/2047156677840b0159a41ab7db4214ce.png
???? How do I do this
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OpenStudy (anonymous):
@jim_thompson5910 Hey if you aren't busy, do you know how to do this??
OpenStudy (anonymous):
you have to use pythagorean theorem twice
AB^2 + BC^2 = AC^2
then
AC^2 + CD^2 = AD^2
OpenStudy (anonymous):
How do I get the lengths of AC to do this?
OpenStudy (anonymous):
use the square root
AC^2 = AB^2 + BC^2
AC = √ ( AB^2 + BC^2)
OpenStudy (anonymous):
Ok I did it and the square root of 24 would be 4.898 but without square rooting it its just 24
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OpenStudy (anonymous):
so AC is 24??
OpenStudy (anonymous):
AC = √ 12^2 + 12^2
AC = √ 288
OpenStudy (anonymous):
16.970 is what I get when I Square root 288
so ac is 16.970/17 if we round it?
OpenStudy (anonymous):
its better if you dont approximate it
AC = √288
now plug it into the second pythagorean equation
AC^2 + CD^2 = AD^2
OpenStudy (anonymous):
24.97
So AD is 24.97?
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OpenStudy (anonymous):
AC^2 + CD^2 = AD^2
√(288)^2 + 8^2 = AD^2
288 + 64 = AD^2
352 = AD^2
AD = √352
OpenStudy (anonymous):
18.761 then?
OpenStudy (anonymous):
which is 18.76 to the nearest hundredth
OpenStudy (anonymous):
Thank you !! That's all or?
OpenStudy (anonymous):
thats it. :)
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OpenStudy (anonymous):
I appreciate your help !! You are very smart
OpenStudy (anonymous):
Yes !! I see them now
OpenStudy (anonymous):
Yes !! I see them now
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