Question

ll

Answer 1

@Cardinal_Carlo

Answer 2

@Cardinal_Carlo

Answer 3

@Cardinal_Carlo

Answer 4

Okay, now I see it.

Answer 5

ok, thanks!

Answer 6

This one's a mouthful.

Answer 7

i know :-(

Answer 8

So our function is this:
\[f(x) = \frac{ (x - 6)(x + 3)(x + 4) }{ (x + 6)(x - 3)(x - 4) }\]
Undefined functions are, in this case, when the denominator equals to zero. So we only need the bottom half of this fraction:
\[0 = (x + 6)(x - 3)(x - 4)\]
This would give us our undefined x-values.
\[x = -6\]\[x = 3\]\[x = 4\]
These are undefined x-values because when plugged in, they make the denominator equal to zero, and therefore makes the entire function f(x) undefined.

Answer 9

oh wow, ok thank you

Answer 10

how are you so good at every math? @Cardinal_Carlo I need to be this good at math haha!

Answer 11

I have just two more left! I could really use help !

Answer 12

Just post them up and close this one ^_^