Question

PLEASE HELP! URGENT! MEDAL! @solomonzelman

Answer 1

@ParthKohli @zepdrix @SolomonZelman @jigglypuff314

Answer 2

1) You didn't show any work.
2) Have you considered substituting the given values into the slope function?
3) Is your Point-Slope Form good and warmed up?

Answer 3

I didn't sh ow any work because I didn't know how to start it at all.

Answer 4

okay, by plugging in, I got 1/6. What now?

Answer 5

oh wait, do I use the slope and points to find the equation of f(x), then use that to find the tangent, etc.

Answer 6

you are given that

\(\color{#000000 }{ \displaystyle f'(x)=\frac{2x^3+3}{5\color{red}{y}} }\) ??

Answer 7

It's called substitution.

\(Slope(1,6) = \dfrac{2(1)^{2}+3}{5(6)} = \dfrac{2+3}{30} = \dfrac{5}{30} = 1/6\)

Very good.

This is the slope. You are given the point (1,6), or you wouldn't have the slope. Plug and chug from here.

Answer 8

(yeah it's implicit thans for answering my question)

Answer 9

Studygirl, you have the slope and point (1,6)... go ahead, you got it.

Answer 10

Thanks Solomon. I got the equation y = (1/6)x + 35/6

and the approximation for 1.1 I got 361/60

Answer 11

Yup, that is right.

Answer 12

I am not sure why you aren't using decimal though...

Answer 13

This value is an approximation anyway, afterall.

Answer 14

(( but the answer is correct ))

Answer 15

thanks