Question

(2x+3)≤3

Answer 1

Are you solving for x? Or converting to set notation?

Answer 2

Im not sure this is weird, I think I need two points on a graph.

Answer 3

Aaahh, I see.~

You simply need to put it in interval notation. So, your answer would be [-3, 0].

Answer 4

How?

Answer 5

and It says I got it wrong

Answer 6

Did you place it in the specified brackets?

Answer 7

I used these but hold on let me pass on and maybe you can help with the next one.

Answer 8

(-8x+24) ≤ 16

Answer 9

Do tell me, does it use | or ( ?

Answer 10

the problem uses | but it usually takes ()

Answer 11

|-8x+24| ≤ 16

Thats how it looks on my screen.

Answer 12

Now, remember to use the " [] "brackets, because they actually matter.
So, your answer would be [1, 5].

Answer 13

Ok that was right. Thanks, but if you don't mind how did you get the answer?

Answer 14

Allow me to write it out for you.~

Answer 15

ok thank you!

Answer 16

Do tell me if that helps! Forgive the long wait.

http://puu.sh/lZ1bJ/fae1ccaf64.png

Answer 17

I think...I understood the whole plotting part better in my head. It's meant to be "Plot it!", my bad.~

Answer 18

well uh where did the 1 come from

Answer 19

The brackets indicate that you can only use numbers 1-5. If you were to put in 0, it would be:
24 ≤ 16 <---- Not true, could never happen.

Answer 20

Your maximum x value is 5, so the question you need to ask is.."how low can I go?"

In this case, the lowest you can go is 1.

Answer 21

So x would equal 2 in this?

|-4x-14|≤6

Answer 22

Actually, it would be -5.

I do applaud you on a nice try, though.~

Answer 23

So where did I mess up? I did it like you did it, and I got 2

Answer 24

Oh, I was mixing myself up with another number.

When you work it out, you should get:
x = -2

Answer 25

Why wouldn't it equal pos 2? Two negatives make a positive correct?