Solve : 9^x=45 Help ASAP
x=log45/2log3
is that the answer or i solve for that
its the answer
can you show me the steps?
@MrCoolGuy
\(\Large \color{#000000 }{ \displaystyle a^{\color{red}{b}} =c}\) \(\Large \color{#000000 }{ \displaystyle \log_a( a^{\color{red}{b}} )=\log_a(c)}\) \(\Large \color{#000000 }{ \displaystyle \color{red}{b}\log_a( a)=\log_a(c)}\) \(\Large \color{#000000 }{ \displaystyle \color{red}{b}=\log_a(c)}\)
I hope this makes it a little easier on the eyes, but according to @SolomonZelman reference, you should be able to apply the rule flawlessly.~
oh so it is right thank you
If you apply the rules of logarithms\( ; \) ■ Rule 1: \(\color{#000000 }{ \displaystyle \log_x (x)=1}\) (for positive x, except x=1) ■ Rule 2: \(\color{#000000 }{ \displaystyle \log_x (x^y)=y\times \log_x(x) }\) (for all exponents "y", the exponent goes on outside as shown)
If you want examples, proves, or other references of anything, let me know.
O.O
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