Question

Am I right?
http://prntscr.com/9fndiw

Answer 1

no

Answer 2

When you expand something like
\(\color{#000000 }{ \displaystyle (b-c)a }\)

you get
\(\color{#000000 }{ \displaystyle b\cdot a-c\cdot a }\)

but, NOT the other way around,
\(\color{#ff0000 }{ \displaystyle c\cdot a-b\cdot a }\)

Answer 3

so B.?

Answer 4

(sorry im a little confused)

Answer 5

I showed you the rule,
\(\color{#000000 }{ \displaystyle (b-c)a =(b\cdot a) - (c\cdot a)}\)
--------------------------
Think about it, based on the example below;
\(\color{#000000 }{ \displaystyle (7-5)3=(7\cdot 3)-(5\cdot 3) }\)
I got the above result when applying the "rule".
Now, I will simplify both sides and calculate.
\(\color{#000000 }{ \displaystyle (7-5)3=(7\cdot 3)-(5\cdot 3) }\)
\(\color{#000000 }{ \displaystyle 2\cdot3=(21)-(15) }\)
\(\color{#000000 }{ \displaystyle 6=6 }\)

Answer 6

Wouldn't you agree then this rule works for all a, b, & c.

Answer 7

This is how I solved for it:
(4−3m)(8)
=(4+−3m)(8)
=(4)(8)+(−3m)(8)
=32−24m

Answer 8

\(\color{#000000 }{ \displaystyle (\color{red}{4}-\color{blue}{3m})8 =(\color{red}{4}\cdot 8) - (\color{blue}{3m}\cdot 8)}\)

that is how the rule is applied in THIS case.

Answer 9

I think I see what it means now so basically the rule has to go along with it,

Answer 10

thanks to both of you lol I'm not good at math

Answer 11

I am not either ... :)

Answer 12

yw

Answer 13

I am not to good at it aswell heh.

Answer 14

:3