Question

Integrate

Answer 1

\[\int\limits_{0}^{24} \sqrt{6x} dx\]

Answer 2

You should not be struggling with this. \(\int x^{1/2}\;dx\)?

Answer 3

So far i got...

\[\int\limits_{0}^{24} (6x)^{1/2} dx\]

Answer 4

Good. Why not just drag the constant out of the way? \(\sqrt{6}\int x^{1/2}\;dx\)

Answer 5

Then I did..

\[6^{1/2}\int\limits_{0}^{24} x ^{1/2} dx\]

Answer 6

Then, what do we do with such exponents?

Answer 7

I don't know...I got stuck in solving the rest of the parts

Answer 8

Pretty sure you;ve seen it. You're just not putting it together,

\(\int x^{n}\;dx = \dfrac{x^{n+1}}{n+1} + C\) except where \(n = -1\).

Answer 9

It's not just integers. It's fractions, too.

Answer 10

1/2+1 / 1/2+1?

Answer 11

1/2 + 1 = 3/2

\(\dfrac{x^{3/2}}{3/2} + C\)?