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Mathematics 18 Online
OpenStudy (arianna1453):

NEED HELP with calculus. Will fan and medal**

OpenStudy (arianna1453):

OpenStudy (denonakavro):

Hey find just open the brackets and then use the vertex formula, if you dont know how to just tell me

OpenStudy (arianna1453):

I dont understand

OpenStudy (denonakavro):

Ok.... Step one (X-4)(6-2X) 6X-2X^2-24+8X -2X^2+14X-24

OpenStudy (denonakavro):

Now use the vertex formula which is -b/2a ...

OpenStudy (openstudier):

Step 1: Find the critical points. Since f'(x) is already factored, we know the solutions to f'(x) = 0 will be 4 and 3. Step 2: To determine which one is the relative minimum, we use the second derivative test where we plug either 4 or 3 and if we get f''(x) > 0, then that value is the relative minimum.

OpenStudy (arianna1453):

Plugging them in you get 0 for both. I have already done that.

OpenStudy (arianna1453):

So would the answer be D, non of these?

OpenStudy (openstudier):

So, like how @denonakavro had expanded f'(x) already, we have f'(x) = \[-2x^2+14x-24\]Now we find f"(x) = \[-4x+14\]To find the relative minimum, we plug in the values of 4 and 3 into f''(x) and if f''(x) > 0 for that value, the second derivative test tells us that it is a relative minimum.

OpenStudy (openstudier):

Do you understand so far?

OpenStudy (arianna1453):

f''(4)= -2 f''(3)= 2 So the relative minimum is going to be 3, correct?

OpenStudy (openstudier):

Yep! Nice job!

OpenStudy (arianna1453):

Can you help me with another?

OpenStudy (openstudier):

Sure, just close this question and post it as another question so others can also look at it.

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