NEED HELP with calculus. Will fan and medal**
Hey find just open the brackets and then use the vertex formula, if you dont know how to just tell me
I dont understand
Ok.... Step one (X-4)(6-2X) 6X-2X^2-24+8X -2X^2+14X-24
Now use the vertex formula which is -b/2a ...
Step 1: Find the critical points. Since f'(x) is already factored, we know the solutions to f'(x) = 0 will be 4 and 3. Step 2: To determine which one is the relative minimum, we use the second derivative test where we plug either 4 or 3 and if we get f''(x) > 0, then that value is the relative minimum.
Plugging them in you get 0 for both. I have already done that.
So would the answer be D, non of these?
So, like how @denonakavro had expanded f'(x) already, we have f'(x) = \[-2x^2+14x-24\]Now we find f"(x) = \[-4x+14\]To find the relative minimum, we plug in the values of 4 and 3 into f''(x) and if f''(x) > 0 for that value, the second derivative test tells us that it is a relative minimum.
Do you understand so far?
f''(4)= -2 f''(3)= 2 So the relative minimum is going to be 3, correct?
Yep! Nice job!
Can you help me with another?
Sure, just close this question and post it as another question so others can also look at it.
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