Question

URGENT HELP PLEASE! MEDAL AND FAN!
7−0.5(0.35−0.15)2+0.19

Answer 1

Just follow the rules of PEMDAS: Parenthesis, Exponents, Multiplication and Division, and Addition and Subtraction.

Answer 2

1. Assuming A, B, C are mutually independent, with P(A) = P(B) = P(C) = 0.1, compute:
(a) P(A ∪ B) Solution: P(A) + P(B) − P(A)P(B) =
(b) P(A∪B∪C)
Solution: By formula the formula for P(A∪B∪C) and indep., P(A∪B∪C) = 3·0.1−3·0.12 +0.13 =
(c) P(A\(B∪C))
Solution: P(A)−P(A∩B)−P(A∩C)+P(A∩B∩C)=

Answer 3

@bunnielover948 I did follow PEMDAS, I got the wrong answer

Answer 4

@maddieprough That really confuses me XD

Answer 5

So it looks like this? \[\large \sf 7-~.5(.25-.25)^{2}+.19\]

Answer 6

Typo in the parentheses but otherwise?

Answer 7

\[\large \sf 7-~.5(.35-.15)^{2}+.19?\]

Answer 8

Uhhmm...

Answer 9

maybe it's 7−0.5 x (0.35−0.15) x 2+0.19

Answer 10

6.5 x 0.2 x 2.19, only if it follows what i said above

Answer 11

Oh wait, the two in it is the power of two (squared) Ooops

Answer 12

That's not right bunnielover...

Answer 13

ok

Answer 14

So was mine correct? \[\large \sf 7-~.5(.35-.15)^{2}+.19]\]

Answer 15

Yes
except not the bracket
at the end

Answer 16

I got 7.17, but that's not on the list of answers that I have to select

Answer 17

the list of answers to select are: 0.49, 0.69, 0.84, 0.87

Answer 18

First step is .35-.15=?

Answer 19

that question is directed to you @DatStudyGirl

Answer 20

Yes, that equals 0.20

Answer 21

Next step is \(\large \sf .2 \times .2 =?\)

Answer 22

that's obviously .4

Answer 23

Actually it would be .04

Answer 24

oh oops yeah, typo

Answer 25

sorry, i dont know why it didn't put in the 0 in .04

Answer 26

So now \(\large \sf .5 \times .04=?\)

Answer 27

.02?

Answer 28

I'm not good with decimals and fractions. :(

Answer 29

Correct. But the answer doesn't come from this, so I am a bit confused now

Answer 30

Hmmm

Answer 31

if the answer is to be less than one, the multiplication between the .5 and parentheses must equal somewhere around 6, which is impossible if they are are decimals.

Answer 32

Yeah, thats why I'm so confused

Answer 33

It would make more sense if it was .7, not 7

Answer 34

In fact, if it was .7, you would actually get one of the answers

Answer 35

Are you sure it's not actually .7?

Answer 36

Yeah.. I'm sure.. What would it be if it was .7?

Answer 37

Cause then it would be \[\large \sf .7-.02+.19\\\large \sf .68+.19\\\large \sf .87\]

Answer 38

Ohh.. hmm, I can contact my teacher about that, maybe she typo'd it. Thanks!

Answer 39

Ye no problem (:

Answer 40

:) Bye

Answer 41

Bye

Answer 42

okay so everyone explaining here made me super confused so i entered it in an online calculator...
https://www.symbolab.com/solver/step-by-step/7%E2%88%920.5%5Cleft(0.35%E2%88%920.15%5Cright)2%2B0.19/?origin=enterkey

Answer 43

thats your answer