Question

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

F. 4
G. 14
H. 16
J. 20
K. 50

Answer 1

3x^2

Answer 2

or 3X2

Answer 3

thanx

Answer 4

nonono

Answer 5

i am asking the question. Is the equation 3x squared?

Answer 6

yes

Answer 7

Ok take what thy gave you and plug it into the equations
3x^2 – 2y exceed the value of 2x^2 – 3y
\[\huge~\rm~\bf~3(3)^2-2(5)=?\]
\[\huge~\rm~\bf~2(3)^2-3(5)=? \]

Answer 8

ok

Answer 9

Can you solve the 2 equations?

Answer 10

yes

Answer 11

Ok solve them and tell me what you get :)

Answer 12

2^2

Answer 13

Not quite..
1)
3^2=?

Answer 14

oh

Answer 15

(2)
2^2

Answer 16

sory 3^2

Answer 17

Not quite...lets solve the first one
=(2)(9)−(3)(5)
=18−(3)(5)
=18−15
18-15=?

Answer 18

3

Answer 19

Good so 1) 3
Now can you try to solve the 2nd one?
\[\huge~\rm~\bf~2(3)^2-3(5)=?\]
This one.

Answer 20

3^2

Answer 21

Are you familiar with how to solve these?

Answer 22

no

Answer 23

Ok first lets get rid of the exponent
\[\huge~\rm~\bf~3^2=3 \times 3=? \]

Answer 24

then the 2

Answer 25

Nope
3 x 3=?

Answer 26

9

Answer 27

Good now we have
\[\huge~\rm~\bf~(2)(9)−(3)(5) \]
2 x 9=?
3 x 5-?

Answer 28

18 and 15

Answer 29

Good :)
18-15=?

Answer 30

3

Answer 31

Good so one of our numbers is 3
using the same method try this one
\[ \huge~\rm~\bf~3(3)^2−2(5)=?\]

Answer 32

3

Answer 33

\[\huge~\rm~\bf~3(3)^2−2(5)=17\]
\[\huge~\rm~\bf~2(3)^2−3(5)=3\]

Ok now do 17-3=?
They want to know how much it exceeded we can find out by subtracting
17-3=?

Answer 34

14

Answer 35

Good and that would be our final answer :)

Answer 36

yes

Answer 37

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Answer 38

thanx

Answer 39

yw ^_^

Answer 40

;]

Answer 41

;-)

Answer 42

^/^