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Show that the function g(x)=x+3/2 is the inverse of f(x) = 2x -3
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hint: you have to check that these subsequent conditions hold: \[\Large g\left( {f\left( x \right)} \right) = 1,\quad f\left( {g\left( x \right)} \right) = 1\]
What do you mean?
for example, I start with the first condition: \[\Large g\left( {f\left( x \right)} \right) = \frac{{f\left( x \right) + 3}}{2} = \frac{{\left( {2x - 3} \right) + 3}}{2} = ...?\]
Michele, don't you mean "x" instead of "1" in your statement above?
An alternative approach would be to start with f(x)=2x+3 and find the inverse function. Takes only a moment or two. Rewrite f(x)=2x+3 as y=2x+3. Interchange "x" and "y". Type in your result here.
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yes! you are right! Thanks for your reply! :) @mathmale
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