A) On the accompanying grid, graph the equation 2y=2x squared -4 in the interval -3 is

Question

A) On the accompanying grid, graph the equation 2y=2x squared -4 in the interval -3 is < (with the line under it) x < (with the line under it) 3 and label it a. 
b) On the same grid, sketch the image of a under T5,-2 after the r x-axis and label it b

campbell_st · Answer

so you are being asked to graph 

$$2y = 2x^2 - 4$$

on the interval $$-3 \le x \le 3$$

is that correct...?

a_ryba · Answer

yes

campbell_st · Answer

ok... start by dividing each term in the equation by 2 and you get

$$y = x^2 - 2$$

is that ok...?

a_ryba · Answer

I understand that part

campbell_st · Answer

now use a table of values such as 

|dw:1450731738806:dw|

just substitute each x, value into the modified equation to get a y- value and plot the points on the number plane. 

in doing this you will get the y- value when x = -2

I did the 1st y value in the table, when x = -3

$$y = (-3)^2 - 2$$

hope it helps...

campbell_st · Answer

you just need to be careful when you square negatives... as it will always be a positive number.

a_ryba · Answer

For the numbers in the chart, how did you come up with them and how did you get 7 as the first y value?

campbell_st · Answer

well 

$$(-3)^2 = -3 \times -3 = 9$$

so then from the equation 

$$y = x^2 - 7$$

you get 

$$y = (-3)^2 - 2 = 9-2 = 7$$

a_ryba · Answer

tbh I'm completely lost and not understanding

campbell_st · Answer

ok... so the equation becomes 

$$y = x^2 - 2$$

now take each x value in the table and substitute it into the equation 

so when x = -3 

$$y = (-3)^2 - 2 = 7$$

so you will plot a point (-3, 7) on the grid

next choose x = -2 and substitute 

$$y = (-2)^2 - 2 = 2$$

so the next y- value is 2  |dw:1450732363182:dw|

so plot the point (-2, 2) on the grid. 

You need to repeat the process for each x value so you get a point you can plot on the number plane. 

just like this

|dw:1450732424305:dw|