Question

The coordinates of 3 of the vertices of a parallelogram are (–3, 4), (–2, 1), and (2, 6). What is the equation for the line containing the side opposite the side containing the first two vertices? (Remember, opposite sides of a parallelogram are parallel.)

Answer 1

Use the slope intercept form\[y=mx+c\]where\[y=vertical~axis\]\[x=horizontal~axis\]\[m=slope\]\[c=y-intercept\]

Answer 2

use these two points (-3,4) and (-2,1) to find the slope

Answer 3

\[formula~for~slope\]\[m=\frac{ y_2-y_1 }{ x_2-x_1 }\]

Answer 4

i got -3/1

Answer 5

good :)

Answer 6

so the slope will be m=-3

Answer 7

so would it be B y=-3x+12

Answer 8

Let me check

Answer 9

Parallel lines hv same slope which is m=-3
use this point(2,6) to find c(y-intercept)
\[y=mx+c\]\[6=-3(2)+c\]add both sides by 6\[c=6+6\]\[c=12\]\[Therefore,the~equation~is~y=-3x+12\]

Answer 10

okay thank you so much

Answer 11

answer is D and u r correct :)

Answer 12

np

Answer 13

Btw,\[\huge{Welcome~To~OpenStudy}\]@cstringer