The molar mass of carbon dioxide (CO2) is 44.01 g/mol. The molar mass of water (H2O) is 18.01 g/mol. A reaction uses 528 g of CO2. How many moles of water are used in this reaction?

Question

imqwerty · Answer

reaction between carbon dioxide and water will be as follows-
$CO_2~+~H_2O$  ------>  $H_2CO_3$

now we can see that 1 mole of $CO_2$ reacts with 1 mole of $H_2O$ to give 1 mole of $H_2CO_3$

we are given that 528g of $CO_2$ are used
so moles of $CO_2$ consumed= $\large \frac{Mass}{Molar~Mass}$

Moles of $CO_2$ consumed =$\large \frac{528}{44.01}$
Moles of $CO_2$ consumed =11.99

1 mole of $CO_2$ react with 1 mole of $H_2O$ so 11.99 moles of $O_2$ will react with 11.99 moles of $H_2O$