Question

how can i simplify

Answer 1

can u your work

Answer 2

@dayakar sorry i make a mistake in my calculation

Answer 3

do u get the answer

Answer 4

check my calculation please

Answer 5

ok

Answer 6

\[\frac{ (\cosh x)^2}{ (1+coshx)^2 } - \frac{ (sinhx)^2 }{ (1+coshx)^2 }\]\[=\frac{ \cosh^2x -\sinh^2x}{ (1+coshx)^2 }\] \[=\frac{ 1 }{ (1+ coshx)^2 }\]

Answer 7

next should i square root it?

Answer 8

no u r wrong
what is the lcm

Answer 9

which one? and what is lcm?

Answer 10

which is one is correct ,
above which u have written is different from the below u solved

Answer 11

denominators are different

Answer 12

omg.. im sorry, give me some times please, cause i need to do it from the beginning

Answer 13

I'm sorry to cut in @dayakar but how are the denominators are different.

Answer 14

@Lovelarap ,IN THE above problem denominators doesn't have squares

Answer 15

OOHH, my bad. : (

Answer 16

@Lovelarap ,am i correct

Answer 17

the second one is the correct one

Answer 18

the denominator have square

Answer 19

It seems to be correct. I would be if the second one didn't have the squares.

Answer 20

\[\frac{ \cosh x }{ 1+coshx } -\frac{ \sinh^2x }{ (1+coshx)^2 }\]

Answer 21

That's the answer?

Answer 22

Could you give the original question?

Answer 23

last one is correct

Answer 24

that's the question

Answer 25

it's actually very long differentation problem,

Answer 26

now the answer should be different from the above

Answer 27

\[\frac{ coshx(1+coshx) -(sinhx )^{2}}{ (1+coshx)^{2} }\]

Answer 28

do u complete next steps

Answer 29

\[\frac{ coshx+(coshx)^{2}-(sinhx)^{2} }{ (1+coshx)^{2} }\]

Answer 30

ok i got the answer

Answer 31

thanks so much :)

Answer 32

😀

Answer 33

\[\frac{ (coshx + 1) }{ (coshx+1)^{2}}\]

Answer 34

\[\frac{ 1 }{ (1+coshx) }\]

Answer 35

that's it

Answer 36

😍💕

Answer 37

thank you

Answer 38

welcome