Can someone help me with this please? An expression is shown below: \[3x^3y + 12xy - 3x^2y - 12y\] Part A: Rewrite the expression so that the GCF is factored completely. Part B: Rewrite the expression completely factored. Show the steps of your work. Part C: If the two middle terms were switched so that the expression became 3x3y - 3x2y + 12xy - 12y, would the factored expression no longer be equivalent to your answer in part B? Explain your reasoning. Thanks for helping!
@Hero @pooja195 @Abhisar @triciaal @jigglypuff314 @SolomonZelman @Directrix @mathmale @mathstudent55 @zepdrix
I'll be back in about 10 - 15 minutes
Nvm I'm back. @triciaal can you help?
What does "GCF" mean?
@Zela101 Greatest common factor
What is the GCF here?
Do you know what GCF is, or means? @Needhelpstudying
@Zela101 It's either 3x, 3x3, or 3x3y. idk my brain turned off and I'm sick lol
\[3x^3y + 12xy - 3x^2y - 12y\] is x found in every term?
No.
Is x a GCF then?
Nope
the GCF is all values that they share, 3y is the common factor that they all share. so, factoring it out we get: 3y ( x^3 + 4x - x^2 - 4 )
So the GCF cannot have an x. Eliminate your choices for 3x, 3x^3, or 3x^3y because contains an X or Xs
So the GCF would be 3y?
yes
Yes because there's a factor of 3 obviously and every term has at least 1 y.
part B is basically u showing steps of part A
And I already know how to factor out things. @ayeshaafzal221 Did that for me though. So that answers A.
yes
@ayeshaafzal221 Is it completely factored with the answer you gave me?
@ayeshaafzal221 you should not factor and give out answers like that without walking the users to the answer.
i just factor out y thats not the answer @Zela101
Technically it is lol
The question has more than one part
But it doesn't matter, I know how to factor out as well.
3y* the person has to simplify themselves
that means it has more than one answer
Can you shows us how you factored the expression completely from answer A?
For part b
ok for part C whats ur approach
Sorry guys, I switched the tab
Alright, I'm really sick, so sorry if I'm a bit slow. @ayeshaafzal221 When you factored out the GCF, was that equation completely factored? Like is part B just asking how you factored out the GCF, or is there more factoring after the GCF?
@ayeshaafzal221 You there?
yes i am asking u what approach will u take for part c
do u think switching the terms will effect the outcome?
When did we do part B?
ugggh headache
oh i thought u got part B
No. When you factored out the GCF, was the equation fully factored? Like, am I just supposed to explain how to factor out the GCF for Part B, or am I supposed to factor further?
for part B, start with part A 3y ( x^3 + 4x - x^2 - 4 ) try to factor the stuff inside parenthesis
and show each steps
factor first two terms, and last terms separately
Alright
3y((x^3 + 4x) - (x^2 - 4))
\[3y(x(x^2+4)-(x^2-4))\]
now can you see clearly what ur next step is?
I know what you did, you got divided the first binomial by its GCF
What would the gcf between x^2 and 4 be?
u dont need to worry about GCF in this
But then wut do I do next?
\[3y((x^2+4)(x-1))\]
thats ur answer
wait, why did ur 4 turn into a 1, and where did the x^2 go?
dont u know how to factor ?
see above u got this right 3y((x^3 + 4x) - (x^2 - 4))
\[(x^3+4x)\]
whats a common factor in this ?
x
so it become \[3y(x(x^2+4)-(x^2-4))\]
right
now if u see closely you have two terms \[(x^2+4) and (x^2-4)\]
Oh yeah, I see that
and u have negative in middle
yea
\[3y((x^2+4)(x-1))\]
thats ur part B
wait, can you just explain how you got the - 1 though. Was it something to do with the first term?
if u e|dw:1451011031741:dw|
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