Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Can someone help me with this please? An expression is shown below: \[3x^3y + 12xy - 3x^2y - 12y\] Part A: Rewrite the expression so that the GCF is factored completely. Part B: Rewrite the expression completely factored. Show the steps of your work. Part C: If the two middle terms were switched so that the expression became 3x3y - 3x2y + 12xy - 12y, would the factored expression no longer be equivalent to your answer in part B? Explain your reasoning. Thanks for helping!

OpenStudy (anonymous):

@Hero @pooja195 @Abhisar @triciaal @jigglypuff314 @SolomonZelman @Directrix @mathmale @mathstudent55 @zepdrix

OpenStudy (anonymous):

I'll be back in about 10 - 15 minutes

OpenStudy (anonymous):

Nvm I'm back. @triciaal can you help?

OpenStudy (zela101):

What does "GCF" mean?

OpenStudy (anonymous):

@Zela101 Greatest common factor

OpenStudy (zela101):

What is the GCF here?

Zeronknight (zeronknight):

Do you know what GCF is, or means? @Needhelpstudying

OpenStudy (anonymous):

@Zela101 It's either 3x, 3x3, or 3x3y. idk my brain turned off and I'm sick lol

OpenStudy (zela101):

\[3x^3y + 12xy - 3x^2y - 12y\] is x found in every term?

OpenStudy (anonymous):

No.

OpenStudy (zela101):

Is x a GCF then?

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

the GCF is all values that they share, 3y is the common factor that they all share. so, factoring it out we get: 3y ( x^3 + 4x - x^2 - 4 )

OpenStudy (zela101):

So the GCF cannot have an x. Eliminate your choices for 3x, 3x^3, or 3x^3y because contains an X or Xs

OpenStudy (anonymous):

So the GCF would be 3y?

OpenStudy (anonymous):

yes

OpenStudy (zela101):

Yes because there's a factor of 3 obviously and every term has at least 1 y.

OpenStudy (anonymous):

part B is basically u showing steps of part A

OpenStudy (anonymous):

And I already know how to factor out things. @ayeshaafzal221 Did that for me though. So that answers A.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@ayeshaafzal221 Is it completely factored with the answer you gave me?

OpenStudy (zela101):

@ayeshaafzal221 you should not factor and give out answers like that without walking the users to the answer.

OpenStudy (anonymous):

i just factor out y thats not the answer @Zela101

OpenStudy (anonymous):

Technically it is lol

OpenStudy (zela101):

The question has more than one part

OpenStudy (anonymous):

But it doesn't matter, I know how to factor out as well.

OpenStudy (anonymous):

3y* the person has to simplify themselves

OpenStudy (zela101):

that means it has more than one answer

OpenStudy (zela101):

Can you shows us how you factored the expression completely from answer A?

OpenStudy (zela101):

For part b

OpenStudy (anonymous):

ok for part C whats ur approach

OpenStudy (anonymous):

Sorry guys, I switched the tab

OpenStudy (anonymous):

Alright, I'm really sick, so sorry if I'm a bit slow. @ayeshaafzal221 When you factored out the GCF, was that equation completely factored? Like is part B just asking how you factored out the GCF, or is there more factoring after the GCF?

OpenStudy (anonymous):

@ayeshaafzal221 You there?

OpenStudy (anonymous):

yes i am asking u what approach will u take for part c

OpenStudy (anonymous):

do u think switching the terms will effect the outcome?

OpenStudy (anonymous):

When did we do part B?

OpenStudy (anonymous):

ugggh headache

OpenStudy (anonymous):

oh i thought u got part B

OpenStudy (anonymous):

No. When you factored out the GCF, was the equation fully factored? Like, am I just supposed to explain how to factor out the GCF for Part B, or am I supposed to factor further?

OpenStudy (anonymous):

for part B, start with part A 3y ( x^3 + 4x - x^2 - 4 ) try to factor the stuff inside parenthesis

OpenStudy (anonymous):

and show each steps

OpenStudy (anonymous):

factor first two terms, and last terms separately

OpenStudy (anonymous):

Alright

OpenStudy (anonymous):

3y((x^3 + 4x) - (x^2 - 4))

OpenStudy (anonymous):

\[3y(x(x^2+4)-(x^2-4))\]

OpenStudy (anonymous):

now can you see clearly what ur next step is?

OpenStudy (anonymous):

I know what you did, you got divided the first binomial by its GCF

OpenStudy (anonymous):

What would the gcf between x^2 and 4 be?

OpenStudy (anonymous):

u dont need to worry about GCF in this

OpenStudy (anonymous):

But then wut do I do next?

OpenStudy (anonymous):

\[3y((x^2+4)(x-1))\]

OpenStudy (anonymous):

thats ur answer

OpenStudy (anonymous):

wait, why did ur 4 turn into a 1, and where did the x^2 go?

OpenStudy (anonymous):

dont u know how to factor ?

OpenStudy (anonymous):

see above u got this right 3y((x^3 + 4x) - (x^2 - 4))

OpenStudy (anonymous):

\[(x^3+4x)\]

OpenStudy (anonymous):

whats a common factor in this ?

OpenStudy (anonymous):

x

OpenStudy (anonymous):

so it become \[3y(x(x^2+4)-(x^2-4))\]

OpenStudy (anonymous):

right

OpenStudy (anonymous):

now if u see closely you have two terms \[(x^2+4) and (x^2-4)\]

OpenStudy (anonymous):

Oh yeah, I see that

OpenStudy (anonymous):

and u have negative in middle

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

\[3y((x^2+4)(x-1))\]

OpenStudy (anonymous):

thats ur part B

OpenStudy (anonymous):

wait, can you just explain how you got the - 1 though. Was it something to do with the first term?

OpenStudy (anonymous):

if u e|dw:1451011031741:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!