Any help is nice. Eliminate the perimeter x=1/2 t, y=(3t^3) - 1
\[x=\frac{ 1 }{ 2 }t , y=3t^3 - 1\]
Ross: Please look up the word "eliminate." Are you sure this is the word you want to use here?
Honestly its not the word choice I would go with but the problem given uses that exact phrasing
Look up "perimeter" also. sure you want to use that word?
i think the wrong word is perimeter ;perhaps should be parameter
Ross, would you want to eliminate perimeters for a living? Think about it.
Parameter. Oops. I read that wrong Its eliminate the parameter. didnt notice till triciaal said something
I seriously hope you will actually look up the words in question. Yes, it's parameter, not perimeter. Makes a huge difference. So, you are to eliminate the parameter here. What is the parameter? Identify it.
Hint: you are given a formula for x and another one for y. Both x and y are functions of what parameter?
Sorry was tabbed out for second. If im correct the goal is to combine the two equations while solving for t
The goal is to eliminate the parameter, t, so that y ou end up with a single equation giving y as a function of x or x as a function of y.
Of the 2 formulas given you, one for x(t) and one for y(t), which would be the easier to solve for t?
x for t. x= 1/2t that would become 2x = t?
You began with x=(1/2)t. Please substitute your 2x=t into that first equation as a check.
x=(1/2)t x=(1/2)2x x=x
OK. Let's go with that. Always good to check. We want to eliminate the parameter, t. What's our next step, using your t=2x?
for each value of t in the equation y=(3t^3) - 1 substitute in 2x? y = (3 * 2x ^3) - 1 y = (6x^3) - 1
You are given the equation y=(3t^3)-1. simply throw out the "t" and write (2x) in its place. We have to be really careful where we place those parentheses.
Think of that y=(3t^3)-1 as\[y=(3)(t)^3-1.\]
I'm suggesting that you throw out the t and replace it with 2x.
Ross?
Sorry was reading that over. Isnt that what I did? Maybe i did the order wrong? \[y=(3)(2x)^3 -1\] so then 8x^3 instead?
Yes, now you have it right. y = 3 (8x^3) - 1. Can you simplify that further?
\[y=24x^3 - 1\] Then that would be the end result?
Yes. So, Ross , you now have an equation for y in terms of x alone, and have succeeded in eliminating the parameter, t. Very good!
Awesome. Thank you Mathmale. Ill close the question now. That helped alot
so glad to hear it! Thx for your perseverance. Merry Christmas!
Join our real-time social learning platform and learn together with your friends!