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Mathematics 19 Online
OpenStudy (anonymous):

Math Check please!

OpenStudy (anonymous):

A scientist is studying the growth of a particular species of plant. He writes the following equation to show the height of the plant f(n), in cm, after n days: f(n) = 10(1.02)n Part A: When the scientist concluded his study, the height of the plant was approximately 11.04 cm. What is a reasonable domain to plot the growth function? Part B: What does the y-intercept of the graph of the function f(n) represent? Part C: What is the average rate of change of the function f(n) from n = 1 to n = 5, and what does it represent?

OpenStudy (mathmale):

f(n) = 10(1.02)n Part A: When the scientist concluded his study, the height of the plant was approximately 11.04 cm. What is a reasonable domain to plot the growth function? Since f(n) represents the plant height, as does 11.04 cm, equate these two and solve the resulting equation for n. Rounding this n up to the nearest integer would give you the upper endpoint of the domain. What would the lower endpoint be?

OpenStudy (anonymous):

Part A: When the scientist concluded his study, the height of the plant was approximately 11.04 cm. What is a reasonable domain to plot the growth function? Answer: Y = 10(1.02) ^ N = Y = 10.2 N = 11.04 11.04 = 10.02 N = 1.08235 = N So, the domain is the number of days, so the number of days would be 0 to 2. Part B: What does the y-intercept of the graph of the function f(n) represent? Answer: What the Y-intercept represents is the height of the plant at the start of the experiment. Part C: What is the average rate of change of the function f(n) from n = 1 to n = 5, and what does it represent? Answer: What the rate of change is the slope of the line from the points ( 1, 10.2) to ( 5, 51 ) We can get the Y coordinate by plugging in the n values 1 and 5. 51 - 10.2 40.8 So, what this number represents ----------------- = --------- = 10.2 is the average amount of growth 5 -1 4 per day for the plant.

OpenStudy (mathmale):

Are you sure that the last question is connected to the rest (i. e., to A and B)? We are told that the plant reaches the height 11.4 cm, a lot shorter than 11.4 cm. What's your own interpretation? You've concluded that the domain, in Part A, is between 1 and 2, but in part C it appears that n ranges from 0 to 5 days.

OpenStudy (anonymous):

Part C: What is the average rate of change of the function f(n) from n = 1 to n = 5, and what does it represent?

OpenStudy (mathmale):

I have a problem with your approach to Part A: Answer: Y = 10(1.02) ^ N = Y = 10.2 N = 11.04 11.04 = 10.02 N = 1.08235 = N So, the domain is the number of days, so the number of days would be 0 to 2. From where does your "10.2 N" come from? Recall "order of operations" rules. Exponentiation takes place before multiplication.

OpenStudy (mathmale):

While I can easily guess your meaning when you type in f(n) = 10(1.02)n, it'd be clearer and a lot more appropriate were you to type it as\[f(n)=10(1.02)^n\]

OpenStudy (anonymous):

yeah, I probably should. Thanks for the help!

OpenStudy (mathmale):

Alternatively, draw this expression:|dw:1451226774756:dw|

OpenStudy (mathmale):

You begin with f(n) = 10(1.02)n, better written as \[f(n)=10(1.02)^n\] and set that equal to 11.4 (cm). Would you please do that now, showing all steps of your solution for n.

OpenStudy (anonymous):

\[0 \le y \le 2 \]

OpenStudy (anonymous):

\[y = 10 ( 1.02) n\]

OpenStudy (anonymous):

it can be rewritten as \[Y = 10.2 n\]

OpenStudy (anonymous):

which then equals 11.04

OpenStudy (anonymous):

Then 11.04 = 10.2n

OpenStudy (anonymous):

\[11.04 \div 10.2 = n\]

OpenStudy (mathmale):

Unfortunately, that is not the case. This assumption is the reason you're having some difficulty. \[11.4=10(1.02)^n\] Order of operations rules require that you do exponentiation first. You have done multiplication first: 10(1.02). NO.

OpenStudy (mathmale):

Your job is to solve \[11.4=10(1.02)^n \] for n. Do not multiply 1.02 by 10.

OpenStudy (mathmale):

Hint: I found a value for n using logarithms.

OpenStudy (mathmale):

Please find n.

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