Question

I don't want a direct answer. I want someone to help me understand the problem, and how to get to the answer. Don't give out the answer please, thanks!


Esmeralda is graphing a polynomial function as a parabola. Before she begins graphing it, explain how to find the vertex. Make sure you include how to determine if it will be a maximum or minimum point. Use an example quadratic function to help you explain and provide its graph.


Thanks for helping!

Answer 1

@zepdrix @mathmale @mathstudent55 @ganeshie8 @sleepyjess

Answer 2

First, I think they mean a quadratic function...

Answer 3

Second, right now I wish I had brought my math book with my across the country, let me see what I can find

Answer 4

K

Answer 5

Are you familiar with the form y = a(x - h)\(^2\) + k

Answer 6

No

I know y = mx + b :)

Answer 7

Like a swag boss

Answer 8

Hmm... that is for the equation of a line. The lesson doesn't cover anything about the equation of a parabola?

Answer 9

The lesson is kinda sucky. It's not compatible with my brain. You @zepdrix @mathmale @mathstudent55 @ganeshie8 and a few others are lol

:)

Answer 10

haha :)
Okay, I'll kinda have to give an answer to explain it, is that okay?

Answer 11

Alright

Answer 12

Okay, this is kinda off topic, but why does it say "high" on the bottom right of my question?

Answer 13

@sleepyjess You've been typing for a while. Where you in the middle of typing when you had a heart attack. ARE YOU OKAY!!!!!

Answer 14

@satellite73

Answer 15

To find the vertex of a parabola, you'll need the equation in vertex form first. Vertex form is y = a(x - h)\(^2\) + k, with h being the x value of the vertex, and k being the y value of the vertex. For example, if we have y = 2(x - 4)\(^2\) + 6, 4 is the h value, and 6 is the k value, making the vertex (4, 6). Now sometimes, we'll have an equation that looks like y = \(2x^2\) + 6x + 8. This is a little trickier. There's a little trick for equations like that. We need to use h = \(\dfrac{-b}{2a}\) and k = f(h). f(h) simply means put in what we found for h into the original equation (\(2x^2\)+ 6x + 8
Let me show you:
\(2x^2\) + 6x + 8

h = \(\dfrac{-6}{2(2)}\)

\(\dfrac{-6}{4}\)

h = -\(\dfrac{3}2\)

now plug that in for x

\(2(-\dfrac 32) ^2\) + 6(\(-\dfrac 32\)) + 8

-3 - 9 + 8

k = -4

so the vertex for that equation is (-\(\dfrac 32\), -4)

Answer 16

Hopefully that all makes sense, if not I'd be happy to explain more :)

Answer 17

@sleepyjess It does make sense. So basically, all you need to do is know what k and h are to find the x and y coordinates. And if nesecarry, use the formula

-b/2a to find the x coordinate

and f(h) to find the y, correct?

Answer 18

Yep :)

Answer 19

You're a quick learner :3

Answer 20

@zepdrix Made me a little familiar with the topic a while ago.

Thanks for helping on this @sleepyjess

UR AWESOME!

Answer 21

@sleepyjess This is off topic, but how many medals do you have?

Answer 22

Like smartcents lol

Answer 23

Oh yeah, the "High" means that when you signed up, the site asked you a question something like, what level will your questions be? Middle, High, College, Grad, etc. YOu must have selected high

Answer 24

Smartcents I have 1310 :)

Answer 25

Or if you were on the site before the update, it asked you the question when you logged on one day

Answer 26

@sleepyjess Oh, I was wondering what it meant lol.

1310?!?!??!?!?!?


I only have 18 :(

Answer 27

I've been on the site for 2 years and 1 day :)

Answer 28

o, that explains it. lol

I want a cool title, like human calculator :(

Anyways, I should probably answer this question, g2g

Oh, and thanks again for helping @sleepyjess !

Answer 29

No problem :)

Answer 30

@sleepyjess Wait, how do I tell if it will be a minimum or a maximum?

Answer 31

If "a" in the equation is positive, it opens upward, meaning the vertex will be a minimum.
If "a" is negative, it opens downward, meaning the vertex will be the maximum