Please help!!! Will fan and medal!!! Question attached in comments
i can help
\[f(x) = \sqrt{8x} ; g(x) = 1/x+6\] is your original equation.
\[\sqrt{8(1/x+6)} = \sqrt{8/x+6}\]
becomes your eqauation when you insert g(x) into f(x)
Okay so how do I find x?
one sec
You don't need to solve for x, once you have f(g(x)), just plug the given solutions into the equation you have. If you get a real answer, it is in the domain. If not, it is not.
Okay lemme see if I can make my calculator work.
so than you check for x=-6 g(x) will be undefined so this mean x=-6 will be eliminate sure - yes ?
you are trying to get the denominator to equal zero so that it is undefined. so the answer would be -6 thanks for explaining it as well @jhonyy9
-6 + 6 = 0 making the entire equation zero :)
0 = 0 for each equation :)
You are looking for a value within the domain of f(g(x)), not the one outside of the domain. -6 is not in the domain, so it can't be the answer.
the only one that it could be in the domain of is positive six right? because anything equal to or lower than -6 isnt in the domain.
so i have said this because you know it sure that for a fraction not can being the denominator never zero - yes - so than this result that -6 will be eliminated from right answers possibility
I'm so lost ._.
How about you guys stop complicating it? And just give here the simplest way of getting the answer?
her*
okay so you have this equation.\[\sqrt{8/x}\]
whoops
√8/x+6
how do you get the bottom of the fraction to = 0?
I don't know ;-;
x+6 is the bottom
And @Alphabet_Sam If you're going to say -6 is incorrect it would be appreciated if you gave the correct answer and the reasoning.
x+6 = 0 (subtract 6 on both sides of the equation) -6 -6 x+0=-6 (simplified)
But I thought it wasn't -6 ;-;
because that makes the bottom of the equation to equal zero; anything that is -6 and lower is incorrect
does that make sense?
So then it would have to be 6? owo
i belive so :)
6 was right :) Would you help with some more? @RhondaSommer
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