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Mathematics 26 Online
OpenStudy (anonymous):

Please help. Will fan and medal. Question attached in comments

OpenStudy (anonymous):

RhondaSommer (rhondasommer):

alright; replace x in f(x) with g(x)

RhondaSommer (rhondasommer):

brb

RhondaSommer (rhondasommer):

need to go eat

OpenStudy (anonymous):

\[\sqrt{4 * 1/x-4}\] ?? and okay I'll be here whenever you're ready

OpenStudy (dannyo19):

Did you try graphing f o g?

OpenStudy (anonymous):

I don't know how to ._.,

OpenStudy (dannyo19):

substitute g(x) in for f(x)

OpenStudy (dannyo19):

so you have f of g(x)...

OpenStudy (anonymous):

Tat's what I was trying to do in that equation above...

OpenStudy (dannyo19):

(that's the function f (g(x)) )

OpenStudy (anonymous):

Okay so how would it look the way you are saying? I've never seen it like that before I don't think so I'm not sure what would be substituted where exactly.

OpenStudy (mathmale):

Write out f(x) and g(x). \Throw out the "x" from f(x), on both sides of the equal sign. Replace it with g(x) = 1/(x-4). This is your f(g(x)). Show your work, please.

OpenStudy (anonymous):

\[f(x) = \sqrt{4x} \] \[g(x)=1/x-4\] \[f(1/x-4)=\sqrt{4*1/x-4}\] @mathmale

OpenStudy (mathmale):

That x-4 must be enclosed in parentheses for max. clarity. Please do that. Combine the 4 and 1 to get 4.

OpenStudy (anonymous):

Sooooo \[f(1/x-4) =\sqrt{4/(x-4)}\] ?

OpenStudy (anonymous):

Is that right? :/

OpenStudy (dannyo19):

right

OpenStudy (anonymous):

So what now?

OpenStudy (dannyo19):

You can graph that function or analyze it given your possible answers.

OpenStudy (dannyo19):

If x is negative you're going to get complex numbers right?

OpenStudy (dannyo19):

If x is 4 you get a function with a real number divided by zero

OpenStudy (dannyo19):

sqrt of -number will not be found in the domain of the graph amongst the reals

OpenStudy (anonymous):

I'm kind of confused by those last three statements ._.,

OpenStudy (dannyo19):

So the Sqrt of 4/ x-4 will have a domain such that x-4 is greater than zero ... Does that make sense to you?

OpenStudy (anonymous):

More than before but not fully

OpenStudy (anonymous):

Ahh okay. So is 5 the answer?

OpenStudy (dannyo19):

Yeah. Cuz the square root of a negative number doesn't exist, and neither does the square root of 4/0 in the case of the domain, since you're only dealing with real numbers.

OpenStudy (dannyo19):

Graphing the function would confirm that 5 is the only number on the list in the domain.

OpenStudy (anonymous):

Thank you.! Can you help me with some more?

OpenStudy (dannyo19):

Yeah sure.

OpenStudy (mathmale):

Please post further questions separately, OK?

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