Question

algebra help

Answer 1

@nincompoop

Answer 2

@Miracrown

Answer 3

@Hayhayz

Answer 4

@Miracrown

Answer 5

Use direct variation \[y=kx\]

Answer 6

Solve for k using y = 12 and x = 15 then you can find your x when you have the value of k for y = 21.

Answer 7

Hey @EKKERKING are you there?

Answer 8

im here

Answer 9

Ok did you figure out k?

Answer 10

i don't know how to put it together i got 2 weeks trying to find out

Answer 11

I told you how to do it, all you have to do is plug in values \[12=k \times 15\] solve for k.

Answer 12

what goes for K?

Answer 13

k is your constant of proportionality once you solve for k we can use it to figure out x for y = 21

Answer 14

so for k i plug in 21?

Answer 15

Noooo, we're solving for k

Answer 16

\[12=k \times 15 \] how do you solve for k here?

Answer 17

i know how to solve this one

Answer 18

k=4/5

Answer 19

Yes exactly.

Answer 20

Now we our constant of proportionality we can use this to solve for x when y = 21 now. \[y = kx \implies 21 = 4/5 x\] solve for x

Answer 21

i got lost here =(

Answer 22

We're just using the same formula, since we know it is directly proportion, do the same thing you did before but solve for x now instead of k as we already have k.

Answer 23

this problem involves "direct variation." A quick Internet search should turn up the general relationship y=kx, where k is the "constant of proportionality."

We have to find the value of k, based upon the given information: y is 12 when x is 15.

I'd suggest you solve y=kx for k: k=y/x

Now substitute the given values of x and y to determine k.

Substitute this value of k into your y=kx.

Now let y=21 and find the value of x that corresponds to y=21.

Answer 24

Please show your work, OK?