Will medal and fan!! Find all solutions to the equation. (cos^2)x + (2 cos x) + 1 = 0
@Michele_Laino
could you first find 2 values of cos x ? its a quadratic in cos x......
let y = cos x y^2 +2y +1 = 0
Sorry I'm confused >_< From what they've been teaching me, I'm supposed to isolate the trig. part, and then add 2πn to each solution..?
yes, all that was just to isolate (or find the multiple values of) the trig part which is cos x here. since the equation is quadratic in cos x, it can have multiple values. hence first find them, then we can proceed.
let y = cos x y^2 +2y +1 = 0 y =... hence, cos x = ...
Ohh ok. Is it +1 and +1 again? :/ or (y+1)^2
(y+1)^2 = 0 so y+1 = 0 so, y = -1 cos x = -1 for what values does cos give you -1?
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