Question

What is the solution to the system of equations?
5x+4y=8
x-2y=10

Answer 1

solve for x in the second equation first so we can plug into first one

Answer 2

have you heard of substitution?

Answer 3

no @Photon336

Answer 4

@michelleball477 you can solve for one variable and then plug it back into the second equation. I'll show you how based on what @Mehek.15 said

Answer 5

Let's solve for x in the second equation:

x-2y = 10

to do this we need to get x by itself.

we do this by adding 2y to both sides.

x-2y = 10

This gives us

x = 10 + 2y


make sense so far?

Answer 6

yea

Answer 7

omg. my equation bar froze..

Answer 8

what do you think we need to do now?

x = 2y+10

5x+4y = 8

Answer 9

idk let me work it out

Answer 10

@michelleball477 take a look at this

we need to plug in 2y+10 wherever we see x

so we plug this into 5x

5(2y+10)+4y = 8

now we distribute and get

10y+50+4y = 8

14y+50 = 8

14y = -42

y = -3

Answer 11

so now we have y = -3 we can put this into the second equation

try to follow along here. now that we found y we can easily plug it back into the second equation to find x.

x-2y = 10

x-2(-3) = 10

x+6 = 10

x = 4

so x= 4 and y = -3

and just to check

let's plug this back into the top equation

5x+4y = 8

5(4)+4(-3)

50-12 = 8 so we know that this is our answer

Answer 12

thanks i get it

Answer 13

try to look at this and work backwards, why do you think I substituted for one of the variables first?

Answer 14

@michelleball477