Question

Integration
Just to double check my answer
@ganeshie8 @hartnn

Answer 1

Given\[y=\frac{ 1 }{ 2x-3 }\]find dy/dx.Hence,find\[\int\limits_{}^{}\frac{ 1 }{ (2x-3)^2 }dx\]

Answer 2

ok, whats your dy/dx?

Answer 3

\[\frac{ dy }{ dx }=\frac{ -2 }{ (2x-3)^2 }\]

Answer 4

thats correct.
and the answer to the final integration that you got ?

Answer 5

i got\[\int\limits_{}^{}\frac{ 1 }{ (2x-3)^2 }dx=\frac{ 1 }{ 6-4x }\]

Answer 6

i get the same :)
\(\checkmark \)

Answer 7

Thank you @hartnn :)

Answer 8

welcome ^_^