Question

PLEASE PLEASE PLEASE HELP WILL FAN AND MEDAL!!!

A country's population in 1991 was 136 million. In 2000 it was 141 million. Estimate the population in 2016 using the exponintial growth formula. Round your answer to the nearest million.

P=Ae^kt

Answer 1

I'd suggest that you let 1 represent the year 1991, 2 1992, and so on, up through 16 to represent 2016. Which integer would then represent the year 2000?

Answer 2

In \[A=Pe ^{kt}\]

Answer 3

No. I need the actual number lol one sec. I asked a question like this yesterday but I still am not good at doing them,

Answer 4

you have two constants: One is P, the original population. The other is k, which is called the "growth constant."

Answer 5

Can you use the given info to determine P and ki?

Answer 6

here P ,A,k,t are value know to solve tis problem

Answer 7

One second OS is lagging ><

Answer 8

in problem U wants to find P if t is given but how u find A and k for A and k use given data

Answer 9

You just confused me....

Answer 10

Ask some questions, then. You seem to have experienced a similar math problem in the near past; what could you apply from that experience towards solving this new problem?

Answer 11

Again, the function in question is\[A=Pe ^{kt}\]

Answer 12

But if you just said P is the original population and @Er.Mohd.AMIR aid we're solving for p.

Answer 13

Yes, I see how my comments could have confused you. The formula for population is\[P=Ae ^{kt}\]

Answer 14

You are told that in the year 1991 (which I recommend denoting by t=1), the initial population, A, was 136 (representing 136 million).

Answer 15

You are also told that in 2000 (represented by 9), the population, P, is 141 (for 141 million).

You have two sets of facts, the info necessary for you to find the values A and k.

Once you've done that, you need only substitute t=16 into your equation for the population, P, for the year 2016 (represented by t=16).

Answer 16

where are you getting 9?

Answer 17

There's no9 or representing in this...

Answer 18

1 = t represents the year 1991,
2 reps. 1992,
....
8 reps. 1998
9 reps 1999
10 reps 2000. Sorry. My bad.

Answer 19

But you don't do that for this? I've done it before and though I don't know how to fully do it I know you don't do that.....

Answer 20

I'm sorry you don't care for my approach. Choosing 1 to represent 1991, etc., is a common approach to solving this type of problem. There would be NO advantage to your using 1991, 1992, etc., instead of my suggested 1, 2, 3, etc.

If you want to approach this problem solution in another way, perhaps you'd be better off waiting for another user to help you.

Answer 21

:/ I just don't get that.. it seems like you're pulling numbers out of the air.

Answer 22

if u use scientefic calculator u can use given values

Answer 23

I don't have one @Er.Mohd.AMIR

Answer 24

You'll either need to obtain a suitable calculator (I recommend the latest version of the TI-84), or you'll need to use online calculators. This problem is not one to do with pencil and paper.

Answer 25

simply put t at 1991 is t=1 and p=136 mil.
and for 2000 t=10 since diff in years is 10 and p=141
u get two equations in A and k

Answer 26

I still suggest you should let 1 (not 0) represent 1991.

Right: doing this properly should result in two separate equations for A and k that can be solved simultaneously for those two constants.

Answer 27

where are u?

Answer 28

@whateven: sorry, but I need to get off the 'Net for now. Good luck. Try to get your hands on an appropriate calculator, and review what you did yesterday in a similar problem solving situation.

Answer 29

I had to do kaundry and there's only one p...

Answer 30

136=A e^(1*k)
and 141=A e^(10*k)

Answer 31

first divide these eq.

Answer 32

Ohhhh ok.

Answer 33

but what is e

Answer 34

e=2.718 its Eular no.or exponential no.

Answer 35

will it always be 2.718

Answer 36

yes

Answer 37

e=2.718281828..............................................

Answer 38

its non teminated no.

Answer 39

So i divide e by 1 and 10?

Answer 40

141/136=e^(9k)

Answer 41

taking log both sides wit base e to solve it

Answer 42

"e" is the most common base used in exponential functions.
The calculator you use for these calculations will ideally have a key for "e." You do not need to memorize the value of e for now, but if you're curious, yes, the value is around 2.718.

Once again: You should end up with two separate equations in A and k, and solve these two equations simultaneously for A and k.

Then write out \[P=Ae ^{kt}\].

Substitute t=16 (or whatever) for t, to calculate the probable population in the year 2016.

Answer 43

(am eating almost done sorry. where is this 9 coming from?)

Answer 44

e^10k / e^k= e^(10k-k)= e^9k

Answer 45

You've asked that question before. I was wrong there; t=10 better represents the year 2000. See our previous discussion, above.

Answer 46

if base is same then power is subtract in division

Answer 47

oh ok. so what do we do after that?

Answer 48

u have log in calculator use that

Answer 49

Do you know of an online calculator that will do that?

Answer 50

which OS u use in window a calculator avialable

Answer 51

What?

Answer 52

log (141/136)=9k log e
9 k =0.036105004
k=0.004011667182 since log e=1

Answer 53

use k=0.004

Answer 54

now 136=A* e^k
put k=0.004 get A

Answer 55

@WhatEven finish it quickly

Answer 56

Am here os is lagging

Answer 57

e^0.004=1.004
so A=136/1.004=135.4570

Answer 58

so then 135? :)

Answer 59

its A=135.45 and k=0.004 u get k and A noe P=A e^kt
put t=16 get ans

Answer 60

sorry t=26

Answer 61

so then \[p=135.45*e ^{k26}\]

Answer 62

put value of k also

Answer 63

e^(0.004*26)=e^(0.104)=1.1096

Answer 64

\[p=134.45*e ^{.004*26}\]

Answer 65

P=135.45*1.1096=150.295

Answer 66

fine

Answer 67

fine?

Answer 68

? what

Answer 69

Why did you say fine o.o

Answer 70

if u have good calculator thhen problem is easy

Answer 71

I don't have one. My calculator is broken

Answer 72

fine is for me when i complete something.

Answer 73

ok i m now turnoff from here.

Answer 74

...I don't ave a way to calculate that last part though...

Answer 75

take cal. of any one and solve yourself

Answer 76

what?

Answer 77

use calculaor of any of Ur friend for solving it urself

Answer 78

I do not have a calculator.

Answer 79

I am also home schooled no friends to ask that's the whole reason I use open study if I were in a brick and mortar school I could just ask the teacher

Answer 80

use google and write online calaulator

Answer 81

(Waiting on it to load ._.

Answer 82

wait so 150?