Question

A quadratic equation is shown below:
x2 + 5x + 4 = 0

Part A: Describe the solution(s) to the equation by just determining radicand. show your work.

Part B: Solve 4x2 -12x + 5 = 0 using an appropriate method. Show the steps of your work, and explain why you chose the method used.

Part C: Solve 2x2 -10x + 3 = 0 by using a method different from the one you used in Part B. Show the steps of your work.

Someone help please, Thanks!

Answer 1

@mathstudent55 @sleepyjess @ganeshie8 @pooja195 @ParthKohli

Answer 2

what is the radicand ? do you know ?

Answer 3

No, I have no idea

Answer 4

do you know the quadratic formula ?

Answer 5

Uhmmm

@Nnesha I don't think so

Answer 6

Sorry, I was getting a drink of water lol

Answer 7

then i think you haven't take the notes and directly jumped to the questions
anyways the quadratic formula
is \[\large\rm x=\frac{-b \pm \sqrt{\color{Red}{b^2-4ac}}}{2a} \] the value under the root known as radicand
b^2-4ac radicand also known as discriminant

Answer 8

\(\huge\color{reD}{\rm b^2-4ac}\) `Discriminant`
you can use this to find if the equation is factorable or not/or to find numbers of solutions
if ` b^2-4ac > 0` then there are 2 real zeros

if ` b^2-4ac = 0` then there is one real root
if ` b^2-4ac < 0` then you will get two complex roots (no -x-intercept)

Answer 9

Wait, so how do I answer Part A @Nnesha ?

Answer 10

first find the the radicand value of the given equation by plugging in b ,c values
and then read what i said n my last comment to *describe * the solutions

Answer 11

\[\large\rm Ax^2+Bx+C=0\] quadratic equation where
a= leading coefficient
b= coefficient of x term
c= constant term

Answer 12

x^2 + 5x + 4 = 0
what's a b and c ??

Answer 13

@Nnesha a is 0, b is 5, and c is 4

Answer 14

b^2 - 4ac = 5^2 - 4(0)(4)

Answer 15

= 25, correct?

Answer 16

if a is 0
then 0x^2 should be the same as 0 times x^2=0

Answer 17

it's 1x^2+5x+4=0
a =1 not 0

Answer 18

Oh right, a is 1. I forgot that x^2 is the same as 1x^2

Answer 19

1 is invisible not 0

Answer 20

Right

Answer 21

correct substitute again

Answer 22

5^2 - 4(1)(4) = 25 - 16 = 9, correct?

Answer 23

correct now how would you describe that ?

Answer 24

What do you mean by describe?

Answer 25

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\(\huge\color{reD}{\rm b^2-4ac}\) `Discriminant`
you can use this to find if the equation is factorable or not/or to find numbers of solutions
if ` b^2-4ac > 0` then there are 2 real zeros

if ` b^2-4ac = 0` then there is one real root
if ` b^2-4ac < 0` then you will get two complex roots (no -x-intercept)
\(\color{blue}{\text{End of Quote}}\)

Answer 26

i mean how would you describe solution
if the radicand is 9 then what type of the solution you will get ?

Answer 27

You will get 2 zeroes?

Answer 28

correct 2 *real* roots

Answer 29

one is x and one is y?

Answer 30

now the solutions( x-intercepts) where line intersect the x-axis when y=0