Question

Few m/c questions!

Answer 1

@pooja195

Answer 2

hint:
at the top of the hill we have this situation:

themagnitude of the weight force \(F_G\) is:
\(F_G=m \cdot g\)
whereas the magnitude of the centrifugal force \(F_C\), is:
\(F_C=m \cdot v^2/R\)
so we can write the subsequent ratio:
\[\Large \frac{{{F_G}}}{{{F_C}}} = \frac{{mg}}{{m\frac{{{v^2}}}{R}}} = \frac{{gR}}{{{v^2}}} = \frac{{9.8 \cdot 25}}{{{{14}^2}}} = ...?\]