Question

Picture in comments! Will medal!

Answer 1

Help!!

Answer 2

@surjithayer

Answer 3

then find x by pythagoras's theorem
or by finding cos 15
remember cos 15=cos(45-30)

Answer 4

ok so b=15 and y=125? @surjithayer

Answer 5

so i do 125^2+75^2=21250?

Answer 6

Is that right or no? :(

Answer 7

\[y=125*\frac{ \sqrt{3}-1 }{ \sqrt{3} +1}\times \frac{ \sqrt{3}-1 }{ \sqrt{3}-1 }=125*\frac{ 3+1-2\sqrt{3} }{ 3-1 }\]
\[=125*\frac{ 4-2\sqrt{3} }{ 2 }=125*(2-\sqrt{3})=125(2-1.732)=125*0.268=33.5\]
\[\frac{ 125 }{ x }=\cos 15=\cos \left( 45-30 \right)=\cos 45 \cos 30+\sin 45 \sin 30\]
\[\frac{ 125 }{ x }=\frac{ 1 }{ \sqrt{2} }\frac{ \sqrt{3} }{ \sqrt{2} }+\frac{ 1 }{ \sqrt{2} }\frac{ 1 }{ 2 }=\frac{ \sqrt{3} +1}{ 2\sqrt{2} }\]
\[x=125*\frac{ 2\sqrt{2} }{ \sqrt{3} +1}\times \frac{ \sqrt{3}-1 }{ \sqrt{3}-1 }=125*\frac{ 2\sqrt{2} \left( \sqrt{3} -1\right)}{ 3-1 }\]
\[x=125(\sqrt{6}-\sqrt{2})=?\]

Answer 8

x=25.881?? @surjithayer

Answer 9

or x=25sqrt6-25sqrt2?

Answer 10

\[x=25\sqrt{6}-25\sqrt{2}\]

Answer 11

@surjithayer

Answer 12

\[x=125\sqrt{6}-125\sqrt{2}\]

Answer 13

@surjithayer ok so that's what x equals, but b=15 and y=125 right??