Help please! best answer rewarded thank you !
here b=2+7+2 = 11 in so you can calculate the area
Well, split it into two areas. The area of top little rectangle is: \(\color{#000000 }{ \displaystyle A_{\rm top}=7\times 4 }\) The area of bottom big rectangle is: \(\color{#000000 }{ \displaystyle A_{\rm bottom}=5\times b }\)
@SolomonZelman How is area of smaller rectangle 7 x 4 ???
7 times 2, (not times 4. My bad
But the idea is that: \(\color{#000000 }{ \displaystyle A_{\rm altogether}=A_{\rm top}+A_{\rm bottom} }\) \(\color{#000000 }{ \displaystyle 74=(2\times 7)+(5\times b) }\)
for the larger rectangle one of the sides is 5 in and the other is 11 in can't you calculate the area now???
(not feeling quite well after removing a wisdom tooth)
@Harkirat, you aren't given that that segment is equivalent to two.
maybe the left and right side extensions are not equivalent... (you aren't given that they are equivalent, although that certainly could be the case)
in such problems the "not given" part in generally symmetrical and hence has to be 2 in
I dont understand at all. o.o
but here you could calculate the area of the smaller rectangle and subtract it from the total given area..
length and breadth of the smaller rectangle is 7 in and 2 in, so its area is 7in x 2in = 14 sq in. total area is given as 74 sq in. so you subtract the area of smaller rectangle from 74 sq in to get your ans
60 sq in. but how do you get the square inches?
7 has the unit in and 2 also has the unit in so in x in gives sq in
Areas are also in sq units
Okay, that makes sense. Thank you!
yes 60 sq in is the correct ans
|dw:1452028020030:dw| I get 55 inches @Harkirat
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