Question

Antiderivative of.... @mathmale @ganeshie8 @ParthKohli @pooja195 @freckles @mathstudent55 @tkhunny

Answer 1

What do I use for u-substitution?
\(\Large \csc(2x)\cot(2x)\)

Answer 2

@mathmale @ganeshie8 @ParthKohli @pooja195 @freckles @mathstudent55 @tkhunny

Answer 3

use cos 2x/sin2x *sin2x
put sin 2x=t

Answer 4

since csc x=1/sin x and cot x=cosx /sin x

Answer 5

Okay, I see what you're saying. I'll try that

Answer 6

Awesome, I think it worked. so far I have 1/u du, which can easily be solved now. Tahnks!

Answer 7

wait, no...

Answer 8

1/u^2 du

Answer 9

the antiderivative of 1/u = ln x

Answer 10

there is sin2x is squre

Answer 11

oh, right! two sin 2x. forgot the exponent 2

Answer 12

is it -csc 2x?

Answer 13

@Er.Mohd.AMIR Is that the correct antiderivative?

Answer 14

(-1/2 ) cse 2x

Answer 15

how'd you get the 1/2 part?

Answer 16

sin 2x =u
cos 2x .2 .dx=du

Answer 17

cos 2x dx=1/2 du

Answer 18

got it

Answer 19

Oh, I forgot to apply the chainrule when finding du/dx

Answer 20

Thank you. :)

Answer 21

welcome